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timama [110]
4 years ago
7

Please answer quick I have a lot of work to do :C

Mathematics
1 answer:
NeTakaya4 years ago
4 0

Answer:

A

Step-by-step explanation:

I hope its correct! :)

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Help????????????????
harkovskaia [24]

This number has decimal digits, so it surely is not integer. This rules out options A and D.

Since the decimal digits are finitely many, the number is rational (you can write it as 1723/1000)

So, the answer is B

3 0
3 years ago
How do you write 0 to the power of 2 on a keyboard and what does is the answer to it?
just olya [345]

Answer:

0^2

Step-by-step explanation:

i think it will be 0 only

6 0
3 years ago
Read 2 more answers
I am unsure about how to solve this problem. May I have some advice how to solve it?
dolphi86 [110]

Answer:

sin ^2 x+ cos ^2 x = 1

Step-by-step explanation:

sin^2 x - cos ^2 x sin ^2 x = sin ^4 x

Factor sin^2 x

sin ^2 x ( 1- cos ^2 x ) = sin ^4 x

Using the identity   sin ^2 x+ cos ^2 x = 1  written as 1 -cos ^2 x = sin ^2 x

sin ^2 x ( sin^2 x ) = sin ^4 x

sin ^4 x = sin ^4 x  

 

6 0
4 years ago
Sausages come in packets of 12. Bread rolls come in packets of 18. Dan wants to buy enough packs of sausages and rolls so that t
boyakko [2]

Answer:

3 packages of sausages and 2 packages of bread rolls.

Step-by-step explanation:

3 times 12 is 36

18 times 2 is 36

7 0
4 years ago
Read 2 more answers
Write any two quadratic equations​.
Thepotemich [5.8K]

To find:

Any two quadratic equations​.

Solution:

The general form of a quadratic equation is:

ax^2+bx+c=0

Where, a,b and c are real number and a is non zero.

We know that a,b,c can take any values but a cannot be 0.

For a=1, b=1,c=1, we get

1x^2+1x+1=0

x^2+x+1=0

One quadratic equation is x^2+x+1=0.

For a=3,b=-1,c=5, we get

3x^2+(-1)x+5=0

3x^2-x+5=0

Therefore, the two quadratic equations are x^2+x+1=0 and 3x^2-x+5=0.

3 0
3 years ago
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