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3 years ago

What she scored on her second test

Mathematics

1 answer:

hjlf3 years ago

3 0

Let's say that Maria had 270 as a total score, which is true.
The problem is asking for an addition problem to help determine the second score Maria might have gotten.

In order to solve this, you need an equation.
Knowing the rules of addition and subtraction, you put 92 and 88 together, and get a sum of 180.

92 + 88 is your addition problem in this question

Now, in order to find the difference, or the second score, you need to subtract.

All you need to do is do a simple equation
↓↓ ↓↓
270 (total of all scores including the second one) - 180 (the sum of the addition equation) = 90

Your answer is 90.

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Given the system of equations, what is the solution? 2x + y = 7 2x - 3y = -1

eduard

Answer: Point Form - (5/2, 2) Equation Form - 5/2, y = 2

Step-by-step explanation:

5 0

2 years ago

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Solve the following equation (If possible please show work)

irina [24]

Answer:

x = 5

Step-by-step explanation:

5(x + 4) - 8 = x + 32

5x + 20 - 8 = x + 32

5x + 12 = x + 32

5x - x + 12 = 32

5x - x = 32 - 12

4x = 32 - 12

4x = 20

x = 5

Hope this helped! :)

4 0

3 years ago

_ Explain how 0.5 and 0.5 are different. Which is greater.

My name is Ann [436]

They aren't different. They are they same. Mistype?

8 0

3 years ago

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I need help solving this problem

Alex787 [66]

Answer:

$(x,f(x)) = (-1,8)$ -- Another point

$a = 8$

Step-by-step explanation:

Given

$f(x) = a|x|$

$(x,f(x)) = (1,8)$

Solving (a): Another point

Substitute 1 for x and 8 for f(x) in $f(x) = a|x|$

$8 = a|1|$

Remove absolute bracket

$8 = a*1$

$8 = a$

$a = 8$

Substitute 8 for a in $f(x) = a|x|$

$f(x) = 8|x|$

Let x = -1

$f(x) = 8|-1|$

Remove absolute bracket

$f(x) = 8*1$

$f(x) = 8$

So, another point is:

$(x,f(x)) = (-1,8)$

Solving (b): The value of a

This has been solved in (a) above

$a = 8$

7 0

2 years ago

2x+8y=3 and 4x-3y=2 value of x and y.. plzz help me

lesya692 [45]

Answer:

Set a system of equations:

$\left \{ {{2x+8y=3} \atop {4x-3y=2}} \right.$

Multiply the whole upper equation by 2 and the whole bottom equation by 1 so their x-value equals:

$\left \{ {{2(2)x+8(2)y=3(2)} \atop {4(1)x-3(1)y=2(1)}} \right.\\\\=\left \{ {{4x+16y=6} \atop {4x-3y=2}} \right.$

Subtract the upper equation by the bottom equation & solve for y:

$(4x-4x)+(16y-(-3y))=6-2\\\\19y=4\\\\y=\frac{4}{19}$

Substitute in the y-value to a equation to find x:

$2x+8y=3\\\\2x+8(\frac{4}{19} )=3\\\\2x=3-\frac{32}{19} =\frac{57}{19} -\frac{32}{19} =\frac{25}{19} \\\\x=\frac{\frac{25}{19}}{2} =\frac{25}{19}*\frac{1}{2} =\frac{25}{38}$

Therefore, the answer would be:

$\left \{ {{y=\frac{4}{19} } \atop {x=\frac{25}{38} }} \right.$

6 0

3 years ago