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3 years ago

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Jack began constructing ΔDEF to be congruent to ΔABC by copying side AC to form DF. Could Jack use ASA to complete the construct

ion? If so, which two angles should he copy?
Yes, he should copy ∠A and ∠B.
Yes, he should copy ∠B and ∠C.
Yes, he should copy ∠A and ∠C.
No, after constructing DF, Jack must copy another side from ΔABC.

2 answers:

Kaylis [27]3 years ago

4 0

Answer:

C). Yes, he should copy ∠A and ∠C.

Step-by-step explanation:

I just did the assignment on Edge... It's 100% correct... Hope this helps!!

Also heart and rate if you found this answer helpful. Have a nice day!! :)

Katarina [22]3 years ago

3 0

Answer:

c. yes, he should copy ∠A and ∠C.

Step-by-step explanation:

just took the test

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Which correlation coefficient would most likely show a weak negative association?

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3 years ago

In a recent study, researchers found that 31 out of 150 boys aged 7-13 were overweight or obese. On the basis of this study can

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Answer:

1) Null hypothesis: $p \leq 0.15$

Alternative hypothesis: $p > 0.15$

2) The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) $z_{crit}= 1.64$

And the rejection zone would be $z>1.64$

4) Calculate the statistic

$z=\frac{0.207 -0.15}{\sqrt{\frac{0.15(1-0.15)}{150}}}=1.955$

5) Statistical decision

For this case our calculated value is on the rejection zone, so we have enough evidence to reject the null hypothesis at 5% of significance and we can conclude that the true proportion is higher than 0.15

Step-by-step explanation:

Data given and notation

n=150 represent the random sample taken

X=21 represent the boys overweight

$\hat p=\frac{31}{150}=0.207$ estimated proportion of boy overweigth

$p_o=0.15$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

1) Concepts and formulas to use

We need to conduct a hypothesis in order to test the true proportion of boys obese is higher than 0.15.:

Null hypothesis: $p \leq 0.15$

Alternative hypothesis: $p > 0.15$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

2) The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Decision rule

For this case we need a value on the normal standard distribution who accumulates 0.05 of the area on the right tail and on this case this value is:

$z_{crit}= 1.64$

And the rejection zone would be $z>1.64$

4) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.207 -0.15}{\sqrt{\frac{0.15(1-0.15)}{150}}}=1.955$

5) Statistical decision

For this case our calculated value is on the rejection zone, so we have enough evidence to reject the null hypothesis at 5% of significance and we can conclude that the true proportion is higher than 0.15

6 0

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Read 2 more answers