Answer:
Step-by-step explanation:
Here, 3.2 centimeters on the map is equivalent to 4 kilometers. We can use unitary method to find, how many kilometer/kilometers each centimeter corresponds to. Using the unitary method: Therefore, the scale of map represents 1.25 kilometers for each centimeter.
I cant see it please send another pic of it. closer to the screen.
Okay, the image is a little tough to see, but I believe it looks something like this:
(5² -10 / 17 - 3 * 4) -1
The first step [remember PEMDAS] is parentheses
Next comes Exponents:
(25 - 10 / 17 - 3 * 4) -1
Then Multiplication:
(25 - 10 / 17 - 12) - 1
Then Division [which we can't do yet since it isn't fully simplified], so we skip to Addition... nothing again, then subtraction.
(15 / 5) - 1
Then we can divide:
(3) - 1
Then subtract!
2
The answer to your problem is 2.
Hope that helps!
Answer: The quotient is (x-2).
Step-by-step explanation:
Since we have given that
![f(x)=(x^3+3x^2-4x-12)\\\\and\\\\g(x)=x^2+5x+6\\\\So,\ \frac{\left(x^3+3x^2-4x-12\right)}{\left(x^2+5x+6\right)}](https://tex.z-dn.net/?f=f%28x%29%3D%28x%5E3%2B3x%5E2-4x-12%29%5C%5C%5C%5Cand%5C%5C%5C%5Cg%28x%29%3Dx%5E2%2B5x%2B6%5C%5C%5C%5CSo%2C%5C%20%5Cfrac%7B%5Cleft%28x%5E3%2B3x%5E2-4x-12%5Cright%29%7D%7B%5Cleft%28x%5E2%2B5x%2B6%5Cright%29%7D)
Now, we have to find the quotient of the above expression.
So, here we go:
![Factorise\ (x^3+3x^2-4x-12)\\\\=\left(x^3+3x^2\right)+\left(-4x-12\right)\\\\=-4\left(x+3\right)+x^2\left(x+3\right)\\\\=\left(x+3\right)\left(x^2-4\right)](https://tex.z-dn.net/?f=Factorise%5C%20%28x%5E3%2B3x%5E2-4x-12%29%5C%5C%5C%5C%3D%5Cleft%28x%5E3%2B3x%5E2%5Cright%29%2B%5Cleft%28-4x-12%5Cright%29%5C%5C%5C%5C%3D-4%5Cleft%28x%2B3%5Cright%29%2Bx%5E2%5Cleft%28x%2B3%5Cright%29%5C%5C%5C%5C%3D%5Cleft%28x%2B3%5Cright%29%5Cleft%28x%5E2-4%5Cright%29)
Now, we will divide the above simplest form with g(x):
![\frac{\left(x+3\right)\left(x^2-4\right)}{\left(x+2\right)\left(x+3\right)}\\\\=\frac{x^2-4}{x+2}\\\\=\frac{\left(x+2\right)\left(x-2\right)}{x+2}\ using\ (a^2-b^2)=(a+b)(a-b)\\\\=x-2](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cleft%28x%2B3%5Cright%29%5Cleft%28x%5E2-4%5Cright%29%7D%7B%5Cleft%28x%2B2%5Cright%29%5Cleft%28x%2B3%5Cright%29%7D%5C%5C%5C%5C%3D%5Cfrac%7Bx%5E2-4%7D%7Bx%2B2%7D%5C%5C%5C%5C%3D%5Cfrac%7B%5Cleft%28x%2B2%5Cright%29%5Cleft%28x-2%5Cright%29%7D%7Bx%2B2%7D%5C%20using%5C%20%28a%5E2-b%5E2%29%3D%28a%2Bb%29%28a-b%29%5C%5C%5C%5C%3Dx-2)
Hence, the quotient is (x-2).