SoMEONE PLEASE HELP ME HURRY!!!
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Answer:
0.0228 = 2.28% probability that a randomly selected firm will earn more than Arc did last year
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Suppose the mean income of firms in the same industry as Arc for a year is 45 million dollars with a standard deviation of 7 million dollars
This means that
What is the probability that a randomly selected firm will earn more than Arc did last year?
Arc earned 59 million, so this is 1 subtracted by the pvalue of Z when X = 59.
has a pvalue of 0.9772
1 - 0.9772 = 0.0228
0.0228 = 2.28% probability that a randomly selected firm will earn more than Arc did last year