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notka56 [123]
4 years ago
13

Bryan plays on the high school basketball team. In his first ten games he scored 12, 14, 8, 9, 8, 16, 8, 13, 22, and 19 points.

Choose and calculate the best measure of central tendency to represent Bryan's scoring over the first ten games. Justify your choice.
Mathematics
1 answer:
galben [10]4 years ago
8 0
The best tendency is the "middle" or "most common" value, so basically it's either the mean or the mode- in this case we use the mode and we can see 12,14,8,9,8, 13, 22 ,19 so 8,8,9,12,13,14,18,22 ; the answer is 13
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95=6x-5(-x-8) <br>Solve for x
Allushta [10]
<span>95=6x-5(-x-8)

Distribute the -5

95 = 6x + 5x + 40

Subtract 40 from both sides and combine like terms

55 = 11x

Divide both sides by 11

x=5</span>
3 0
3 years ago
Read 2 more answers
NEED HELP ASAP BRAINLIEST ANSWER IF CORRECT
Alex_Xolod [135]
If we need sections that are 18 ft. long from available 78 ft. long line than we will divide 78/18 =4.(3)
So we will get 4 sections that are 18 ft. long and we will have a remainder of 6 ft line not used.
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AlexFokin [52]
Pythagorean Therom
a^2 + b^2 = c^2
5^2 +b^2 = 7^2
25=b^2 = 49

49-25=b^2

49-25=14

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b=sqrt24

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4 0
3 years ago
The distribution of prices for home sales in a certain New Jersey county is skewed to the right with a mean of $290,000 and a st
I am Lyosha [343]

Answer:

The probability that the mean of the sample is greater than $325,000

P( X > 3,25,000) = P( Z >2.413) = 0.008

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given the mean of the Population( )= $290,000

Standard deviation of the Population = $145,000

Given the size of the sample 'n' = 100

Given 'X⁻'  be a random variable in Normal distribution

Let   X⁻ = 325,000

Z = \frac{x^{-}-mean }{\frac{S.D}{\sqrt{n} } }  = \frac{325000-290000}{\frac{145000}{\sqrt{100} } }  = 2.413

<u><em>Step(ii):</em></u>-

The probability that the mean of the sample is greater than $325,000

P( X > 3,25,000) = P( Z >2.413)

                           = 0.5 - A(2.413)

                           = 0.5 - 0.4920

                           = 0.008

<u><em>Final answer:-</em></u>

The probability that the mean of the sample is greater than $325,000

P( X > 3,25,000) = P( Z >2.413) = 0.008

6 0
3 years ago
Expand and simplify 4 ( y + 6 ) − 2 ( y − 2 )
elena-14-01-66 [18.8K]

[ Answer ]

\boxed{2y \ + \ 28}

[ Explanation ]

4(y + 6) - 2(y - 2)

[Expand] 4(y + 6): 4y + 24

4y + 24 - 2(y - 2)

[Expand] -2(y - 2): -2y + 4

4y + 24 - 2y + 4

[Simplify] 4y + 24 - 2y + 4: 2y + 28

= 2y + 28

\boxed{[ \ Eclipsed \ ]}

7 0
4 years ago
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