If I have right angle triangle with a hypotenuse of 12meters and an angle of 60degrees what is the length
1 answer:
There are 2 basic trangles used in SAT,
45-45-90
30-60-90
if you look in the attachment you will know the relationship between each so
with a 30-60-90 triangle which you have
hypotonuse=2x
hypotonuse=12
2x=12
divide by 2
x=6
I'm not sure about the length, but I'm assuming you mean the longer side
the measure of each leg is 6 and 6 times√3
the lonnger one is 6√3
the answer is 6√3 meters
45-45-90
30-60-90
if you look in the attachment you will know the relationship between each so
with a 30-60-90 triangle which you have
hypotonuse=2x
hypotonuse=12
2x=12
divide by 2
x=6
I'm not sure about the length, but I'm assuming you mean the longer side
the measure of each leg is 6 and 6 times√3
the lonnger one is 6√3
the answer is 6√3 meters
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Answer:
k = 12
Step-by-step explanation:
Given:
The equation
To find:
Value of for which the given equation has one distinct real solution.
Solution:
The given equation is a quadratic equation.
There are always two solutions of a quadratic equation.
For the equation: to have one distinct solution:
Here,
a = 2,
b = -k and
c = 18
Putting the values, we get:
The equation becomes:
And the one root is:
Answer:
Step-by-step explanation:
A box plot is the diagrammatic representation of the five number summary. It includes 5 items:
The minimum.
Q1 = the first quartile or the 25% mark.
The median.
Q3 = the third quartile or the 75% mark.
The maximum.
Rearranging the data in ascending order, it becomes
169, 163, 153, 166, 149, 148, 146, 145, 152, 163
145, 146, 148, 149, 152, 153, 163, 163, 166, 169
Minimum = 145
Maximum = 169
Median = (152 + 153)/2 = 152.5
The median divides the data into two equal halves. The middle of the lower halve is Q1 while the middle of the upper halve is Q3
Q1 = 148
Q3 = 163
The diagram of the box plot is shown in the attached photo
