Question 4 is d question 3 is c
Step-by-step explanation:
communitive property
Answer:
$1,109.62
Step-by-step explanation:
Let's first compute the <em>future value FV.</em>
In order to see the rule of formation, let's see the value (in $) for the first few years
<u>End of year 0</u>
1,000
<u>End of year 1(capital + interest + new deposit)</u>
1,000*(1.09)+10
<u>End of year 2 (capital + interest + new deposit)</u>
(1,000*(1.09)+10)*1.09 +10 =

<u>End of year 3 (capital + interest + new deposit)</u>

and we can see that at the end of year 50, the future value is

The sum

is the <em>sum of a geometric sequence </em>with common ratio 1.09 and is equal to

and the future value is then

The <em>present value PV</em> is

rounded to the nearest hundredth.
Answer:
EH = 3.31
Step-by-step explanation:
We have been given a right angle triangle EKL. As KH has been given as the altitude (perpendicular) of the right angled triangle, and K is the right angle, we can say that EK is tthe base of the triangle and EH is the only side lleft, which is the hypotenuse of the triangle.
Where,
EK = Base = 3
KH = perpendicular altitude
EH = Hypotenuse
m<K = 90
m<E = 25
We know that
cosθ = Base/ Hypotenuse
cos 25 = 3/ EH
EH = 3/cos25
EH = 3.31
Perpendicular alitutude can also be calculated by using the formula for tanθ.