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VashaNatasha [74]
3 years ago
6

How many prairie dogs are there(round to nearest whole number)

Mathematics
1 answer:
Volgvan3 years ago
8 0

Answer:

can you give more invormation?

Step-by-step explanation:

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NNADVOKAT [17]
I don’t know, what did he say?
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3 years ago
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A company knows that 30% of Customers who come to the store will check out the merchandise and then order it online because it i
valentinak56 [21]
Let X be a discrete random variable with geometric distribution.
 Let x be the number of tests and p the probability of success in each trial, then the probability distribution is:
 P (X = x) = p * (1-p) ^ (x-1). With x = (1, 2, 3 ... n).
 This function measures the probability P of obtaining the first success at the x attempt.
 We need to know the probability of obtaining the first success at the third trial.
  Where a success is defined as a customer buying online.
 The probability of success in each trial is p = 0.3.
 So:
 P (X = 3) = 0.3 * (1-0.3) ^ (3-1)
 P (X = 3) = 0.147
 The probability of obtaining the first success at the third trial is 14.7%
7 0
3 years ago
Apurse contains S 7.55 in quarters and dimes. There are
borishaifa [10]

Answer:

  • 25 quarters
  • 13 dimes

Step-by-step explanation:

If you subtract the extra 12 quarters from the total, you have $4.55 that can be made up of groups of 1 quarter and 1 dime. Since those groups are worth $0.35, there are $4.55/$0.35 = 13 of them.

There are 13 dimes and 13+12 = 25 quarters in the purse.

5 0
3 years ago
At HEB, you can buy a 12 pack of Coke for $5,28 or you can buy a case, 20-pak of cans for $8 78. Which pack offers the better de
Wittaler [7]

Answer:

I think the better deal is $8.78.

Step-by-step explanation:

I think this because half of twenty is 10, and half of 12 is 6. The twelve pack price is closer to one dollar a can, and the 20 pack's is further. :) i hope this helps you!

(plz brainliest! :) )

4 0
3 years ago
The thickness X of aluminum sheets is distributed according to the probability density function f(x) = 450 (x2 - x) if 6 < x
grandymaker [24]

Solution :

Given :

f(x) = \left\{\begin{matrix}\frac{1}{450}(x^2-x) & \text{if  } 6 < x < 12 \\ 0 & \text{otherwise}\end{matrix}\right.

1. Cumulative distribution function

$P(X \leq x) = \int_{- \infty}^x f(x) \ dx$

              $=\int_{- \infty}^6 f(x) dx + \int_{6}^x f(x) dx $

             $=0+\int_6^x \frac{1}{450}(x^2-x) \ dx$

             $=\frac{1}{450} \int_6^x (x^2-x) \ dx$

             $=\frac{1}{450}\left[\frac{x^3}{3}-\frac{x^2}{2}\right]_6^x$

             $=\frac{1}{450}\left[ \left( \frac{x^3}{3} - \frac{x^2}{2}\left) - \left( \frac{6^3}{3} - \frac{6^2}{2} \right) \right]  $

            $=\frac{1}{450}\left[\frac{x^3}{3} - \frac{x^2}{2} - 54 \right]$

2.  Mean $E(x) = \int_{- \infty}^{\infty} \ x \ f(x) \ dx$

                       $=\int_{6}^{12}x . \left( \frac{1}{450} \ (x^2-x)\right)\  dx$

                     $=\frac{1}{450} \int_6^{12} \ (x^3 - x^2) \ dx$

                     $=\frac{1}{450} \left[\frac{x^4}{4} - \frac{x^3}{3} \right]_6^{12} \ dx$

                     $=\frac{1}{450} \left[ \left(\frac{(12)^4}{4} - \frac{(12)^3}{3} \right) -  \left(\frac{(6)^4}{4} - \frac{(6)^3}{3} \right) $

                     $=\frac{1}{450} [4608 - 252]$

                    = 17.2857

5 0
3 years ago
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