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mariarad [96]
2 years ago
9

Is the book at rest or in motion

Mathematics
1 answer:
lubasha [3.4K]2 years ago
4 0
The book is in motion. Hope this answers your question!
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Will give brainliest, Please explain how you got your answer!
Tpy6a [65]
2x + 14 + 6y (multiply everything by 2)
6 0
2 years ago
What is the intersection of the given lines AE and DE?
cricket20 [7]

Given statement is "What is the intersection of the given lines AE and DE?".

That gives us information that there are two lines named AE and DE which intersect each other. Now we have to find their intersection point.


If you see carefully the name of both lines AE and DE then you will find that; they have common letter "E" in their name.

That means point "E" lies on both lines.

We know that intersection point always lies on both lines.

Which proves that point "E" is the intersection point.


Hence choice "<u>B. Point E" </u>is the final answer.

7 0
2 years ago
Why did the bulletin board notice feel nervous
Gre4nikov [31]
The reason why the bulletin board notice feel nervous is: it was under a tack In most common cases, the notice that is putted under a tack is intended to be displayed on the board for a pretty long time, highlighting the importance and the urgeny of the notice.
3 0
3 years ago
Find the perimeter of the figure. Round all figures to the nearest hundredths place. Isosceles trapezoid
zhannawk [14.2K]

Answer:

d. 92.84

Step-by-step explanation:

The top edge overhangs the bottom edge by (39 -27)/2 = 6 ft on both ends. This makes the slant side have length  

.. √((6 ft)^2 +(12 ft)^2) = 6√5 ft

Then the perimeter is

.. (39 +6√5 +27 +6√5) ft = 66 +12√5 ft

= 92.83 ft

6 0
3 years ago
A wire that is 0.20 meters long is moved perpendicularly through a magnetic field of strength 0.45 newtons/amperes meter at a sp
Natali [406]

Answer:

Given:

length of the wire = 0.20 meters

magnetic field strength = 0.45 newtons/amperes meter

speed = 10.0 meters per second

emf = B * l * v 

B = flux density ; l = length of the wire ; v = velocity of the conductor

emf = 0.45 newtons / ampere meter * 0.20 meters * 10.0 meters/seconds

emf = 0.90 volts

The emf produced is 0.90 volts.

Step-by-step explanation:

6 0
2 years ago
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