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kogti [31]
3 years ago
7

WILL MARK BRAINLIEST!!!

Mathematics
2 answers:
Art [367]3 years ago
8 0

Answer:

<em>I think the best answer will be is</em><em> C. 1.3 Good Luck!</em>

professor190 [17]3 years ago
8 0

Answer:

C

Step-by-step explanation:

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Which input value produces the same output value for the two functions on the graph?x = x= –3
MaRussiya [10]

Answer:

x=3

Step-by-step explanation:

Basically the question is asking what value of x gives the same value for y

(or where do the 2 lines cross)

the input is x=3, the out put is y =-1


3 0
4 years ago
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In △ABC, point M is the midpoint of AB , point D∈ AC so that AD:DC=2:5. If AABC=56 yd2, find ABMC, AAMD, and ACMD.
Komok [63]

Since point M is the midpoint of AB, then AM=MB.

Consider the area of the triangles ABC and BMC:

A_{ABC}=\dfrac{1}{2}\cdot AB\cdot h_c=56\ yd^2,

where h_c is the height drawn from the vertex C to the side AB.

So, AB\cdot h_c=112\ yd^2.

Now

A_{BMC}=\dfrac{1}{2}\cdot BM\cdot h_c=\dfrac{1}{2}\cdot \dfrac{AB}{2}\cdot h_c=\dfrac{1}{4}\cdot AB\cdot h_c=\dfrac{1}{4}\cdot 112=28\ yd^2.

Also

A_{AMC}=A_{ABC}-A_{BMC}=56-28=28\ yd^2.

Now consider the area of the triangles AMD and CMD. Let h_M be the height drawn from the point M to the side AC.

A_{AMD}=\dfrac{1}{2}\cdot AD\cdot h_M=\dfrac{1}{2}\cdot \dfrac{2AC}{7}\cdot h_M=\dfrac{2}{7}\cdot \left(\dfrac{1}{2}\cdot AC\cdot h_M\right)=\dfrac{2}{7}\cdot A_{AMC}=\dfrac{2}{7}\cdot 28=8\ yd^2.

Therefore,

A_{MDC}=A_{AMC}-A_{AMD}=28-8=20\ yd^2.

Answer: A_{MBC}=28\ yd^2, A_{AMD}=8\ yd^2, A_{MDC}=20\ yd^2.

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3 years ago
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Nimfa-mama [501]
1 3/4 because you have but how many times 4 goes into 7. Then use the difference as the numerator and use 4 as the bottom
4 0
4 years ago
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Graph y = 4x + 2 where is it grqphed at
cestrela7 [59]
Starting point: (0, 2) and can go to (1, 6).
This shows the slope and y-intercept. Hope this helps.
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3 years ago
La suma de tres numeros consecutivos
Kisachek [45]
1+2+3=6

4+5+6=15

3+4+5=12
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4 years ago
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