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Answer:
you need to send a picture of the table
Step-by-step explanation:
No one can help without the numbers.
Answer:
the answer is 3/7
Step-by-step explanation:


Pay attention here because I'm adding an extra letter to our circle to help keep track of the values in our formula. OUTSIDE of the intercepted arc I'm adding the point E. So the major arc is arc BEG and the minor arc is arc BG. The formula then for us is ∠

. We just don't have values for the arcs yet. If the measure of the central angle is 4x+238, then the measure of arcBG is also 4x+238. Around the outside of the circle is 360°. So we will use it in an expression. ArcBEG=360-(4x+238). Fitting that into our formula we have
![2x+146= \frac{1}{2}[(360-4x-238)-(4x+238)]](https://tex.z-dn.net/?f=2x%2B146%3D%20%5Cfrac%7B1%7D%7B2%7D%5B%28360-4x-238%29-%284x%2B238%29%5D%20)
. Doing all the simplifying inside there we have

and

. Multiply both sides by 2 to get rid of the fraction: 4x+292=-8x-116. Combine like terms to get 12x = -408 and divide to solve for x. x = -34. Fourth choice down from the top.
Answer:
We are given that the frame is 2 units wide, which means that we subtract the length of the outer frame by 2 units for each side:
7 - 2 -2 = 3
9 - 2 -2 = 5
Now, we have the length and width for the smaller rectangle, so we use the area formula (area = length*width) to get:
3*5 = 15
Step-by-step explanation:
Please support my answer.