A)
The four small squares are all 3x3, so the perimeter is 3+3+3+3 = 12.
12 * 4 = 48
We can find the perimeter of the large diamond shape using the Pythagorean theorem, a^2 + b^2 = c^2
a = 4
b = 4
4^2 + 4^2 = c^2
16 + 16 = c^2
32 = c^2
c = 5.65685425
So the perimeter of the large diamond shape is
5.65685425+5.65685425+5.65685425+5.65685425 = 22.627417
48+22.6 = 70.6
B)
The areas of the small squares are 3x3 = 9
9 * 4 = 36
The area of the large diamond shape is
5.65685425 * 5.65685425 = 32
36 + 32 = 68
Answer:
The selection of the two marbles are <u>dependent</u> because the selection of the pink marble <u>changes</u> the probability that a green marble is drawn next.
If the pink marble had been put back into the bag, the selection of the two marbles would have been <u>independent</u>
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Explanation:
The key phrase to focus on here is "This marble is placed on a table". It implies that we do not put it back into the bag, and also implies we don't put in a replacement either. Hence we consider this scenario as "no replacement".
In no replacement situations, we always have dependent events. The second selection depends on the first one.
The probability of picking green is 6/11 because there are 6 green out of 5+6 = 11 total. But if we picked a pink one first and didn't put it back, then the 11 drops to 10 and we get 6/10 = 3/5 as the new probability.
In other words,
- before the pink marble is selected, the chances of green are 6/11
- after the pink marble is selected, and not put back, the chances of green are now 6/10 = 3/5
Because this probability changes, it's sufficient evidence to say the event of picking green on the second selection is dependent on the first selection of selecting pink.
If the marble had been put back, then we'd revert back to the original state of the bag. That would mean the chances of green would stay at 6/11. Therefore, situations with replacement lead to independent events.
9514 1404 393
Answer:
15625/4096
Step-by-step explanation:
The sequence is geometric with first term 1 and common ratio 5/4. The general term is ...
an = a1·r^(n-1)
an = 1·(5/4)^(n-1)
Then the 7th term is ...
a7 = (5/4)^(7-1) = 15625/4096
I think it’s A. i’m not very sure tho
X + 12 = n
N is 5 more than twelve so add 5 to 12 and you get 17.