If Each side of an equilateral triangle<span> is 10 m. ... Thus </span>triangle<span> APC is a right</span>triangle<span>. The length of CA is 10 m, and the length of PC is 5 m, and hence you can use Pythagoras' theorem to find the length of AP, which </span>is the height<span> of the </span>triangle<span>ABC.
</span>If Each side of an equilateral triangle<span> is 10 m. ... Thus </span>triangle<span> APC is a right</span>triangle<span>. The length of CA is 10 m, and the length of PC is 5 m, and hence you can use Pythagoras' theorem to find the length of AP, which </span>is the height<span> of the </span>triangleABC.
Answer:
x=4 and y=(-6)
Step-by-step explanation:
Solve for the first variable in one of the equations, then substitute the result into the other equation.
To find the area of a rhombus, multiply the lengths of the two diagonals and divide by 2 The sides and angles of a rhombus The sides of a rhombus are all congruent Opposite angles of a rhombus are congruent
Answer:
25
Step-by-step explanation:
The number that needs to be added is the square of half the x-coefficient:
(-10/2)^2 = 25
_____
Adding that gives ...
(x -5)^2 = 32
x = 5 ± 4√2
Let's solve your equation step-by-step.<span><span><span>2<span>(<span>h−8</span>)</span></span>−h</span>=<span>h−16</span></span>Step 1: Simplify both sides of the equation.<span><span><span>2<span>(<span>h−8</span>)</span></span>−h</span>=<span>h−16</span></span><span>Simplify: (Show steps)</span><span><span>h−16</span>=<span>h−16</span></span>Step 2: Subtract h from both sides.<span><span><span>h−16</span>−h</span>=<span><span>h−16</span>−h</span></span><span><span>−16</span>=<span>−<span>16
</span></span></span>Step 3: Add 16 to both sides.<span><span><span>−16</span>+16</span>=<span><span>−16</span>+16</span></span><span>0=0</span>Answer:<span>All real numbers are solutions.</span>
