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3 years ago

Ten cards are numbered 1 through 10 are all mixed together and one card is drawn. Find the probability of selecting a 3.

Mathematics

1 answer:

garik1379 [7]3 years ago

3 0

the probability of selecting a 3 is 1/10

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Given f(x)=e^-x^3 find the vertical and horizontal asymptotes

Aleonysh [2.5K]

Given:

$f\mleft(x\mright)=e^{-x^3}$

To find the vertical and horizontal asymptotes:

The line x=L is a vertical asymptote of the function f(x) if the limit of the function at this point is infinite.

But, here there is no such point.

Thus, the function f(x) doesn't have a vertical asymptote.

The line y=L is a vertical asymptote of the function f(x) if the limit of the function (either left or right side) at this point is finite.

$\begin{gathered} y=\lim _{x\rightarrow\infty}e^{-x^3} \\ =e^{-\infty} \\ y=0 \\ y=\lim _{x\rightarrow-\infty}e^{-x^3} \\ y=e^{\infty} \\ =\infty \end{gathered}$

Thus, y = 0 is the horizontal asymptote for the given function.

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11 months ago

2b^3+5=2(3)^3+5 when b=3

seraphim [82]

Answer:

2b^3+5=2(3)^3+5 when b=3

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3 years ago

What are the zeros of the polynomial function? f(x)=x2−16x+48

posledela

X1 = 12
X2 = 4
I took the test and can promise you this is correct!!

6 0

3 years ago

Read 2 more answers

A two-factor study with two levels of factor A and three levels of factor B uses a separate group of n = 5 participants in each

Mashcka [7]

Answer: There are 30 participants are needed for the entire study.

Step-by-step explanation:

Since we have given that

Number of levels of factor A = 2

Number of levels of factor B = 3

Number of participants in each treatment condition = 5

So, the number of participants are needed for the entire study is given by

$2\times 3\times 5\\\\=6\times 5\\\\=30$

Hence, there are 30 participants are needed for the entire study.

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3 years ago

5. Use the rules for long division to divide 262 by 9. A. 29r1 B. 28 C. 30 D. 29

vfiekz [6]

Since $270=262+8$ , and $\dfrac{270}9=30$ , we have

$\dfrac{270}9=\dfrac{262}9+\dfrac89$
$\implies30-\dfrac89=\dfrac{262}9$
$\implies29+\dfrac19=\dfrac{262}9$

so the answer is A.

6 0

2 years ago

Ten cards are numbered 1 through 10 are all mixed together and one card is drawn. Find the probability of selecting a 3. ​

Ten cards are numbered 1 through 10 are all mixed together and one card is drawn. Find the probability of selecting a 3.