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n200080 [17]
3 years ago
11

Factor x2 − 8x + 9.

Mathematics
1 answer:
kolezko [41]3 years ago
7 0

x^2 − 8x + 9

What two numbers when multiplied yield 9 but when added yield -8?

There are no such numbers.

Use the quadratic formula.

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Which graph represents 9x2 – 16y2 – 54x + 64y – 127 = 0?
klasskru [66]

Answer:

Right now I'm wondering what kind of class you are taking to get such a weird graph, but I graphed it for you on the screenie.

Step-by-step explanation:

You should though recheck your question for exponents, as 9x2 could be interpreted differently.

Since exponents to not transition well here, I can assume that it was a 9x^2, so please add an exponent symbol ^ between the variables and exponents next time.

3 0
3 years ago
Can you help me on his question
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C 2 (-20)

He withdrew (took out) money twice.
That's -20 two times.
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What is the answer to this 584,405÷884
I am Lyosha [343]

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2 years ago
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Which of the following fractions has the same value as the decimal number 0.65?
boyakko [2]

Answer:

13/20

Step-by-step explanation:

To find this, divide 13 by 20 to get .65

Hope this helped!

4 0
3 years ago
For a medical study, a researcher wishes to select people in the middle 60% of the population based on blood pressure.
Finger [1]

Answer:

Lower limit: 113.28

Upper limit: 126.72

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 120, \sigma = 8

Middle 60%

So it goes from X when Z has a pvalue of 0.5 - 0.6/2 = 0.2 to X when Z has a pvalue of 0.5 + 0.6/2 = 0.8

Lower limit

X when Z has a pvalue of 0.20. So X when Z = -0.84

Z = \frac{X - \mu}{\sigma}

-0.84 = \frac{X - 120}{8}

X - 120 = -0.84*8

X = 113.28

Upper limit

X when Z has a pvalue of 0.80. So X when Z = 0.84

Z = \frac{X - \mu}{\sigma}

0.84 = \frac{X - 120}{8}

X - 120 = 0.84*8

X = 126.72

4 0
3 years ago
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