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maks197457 [2]
3 years ago
8

Which of the following represents the factorization of the binomial below ? x^2 - 144

Mathematics
1 answer:
Dima020 [189]3 years ago
6 0

It factors to (x+12)(x-12)

This is the same as (x-12)(x+12) as we can multiply two expressions in any order we want. This is like saying 7*5 is the same as 5*7

I used the difference of squares rule to factor x^2 - 144. It might help to write x^2 - 144 as x^2 - 12^2, then compare it to a^2 - b^2 = (a-b)(a+b)

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x < 2

Step-by-step explanation:

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Last question for Jim Thompson Geometry homework
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<h3>Answers:</h3>
  • Reason 1:  <u>Given</u>
  • Reason 3: <u>Similar because of SAS</u>

==============================================

Explanation:

At the top of the proof, your teacher states "Given" followed by the relevant useful info. We simply repeat that info word for word as statement 1. This is how all proofs start out. We start with what we're given and try to build toward what we want to prove.

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5 0
2 years ago
Siska wants to buy 5 packs of chocolate , which will cost $ 3,25 each. If ahe pays with 2 sheets of $10 , how much change will s
GarryVolchara [31]

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3 years ago
The rate of growth of profit​ (in millions) from an invention is approximated by Upper P prime (x )equals x e Superscript negati
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Answer:

The function is  P(x) =  \frac{1}{2} e^{-x^2} +0.016

Step-by-step explanation:

From the question we are told that

    The rate of growth  is  P'(x) =  xe^{x} - x^2

     The total profit is P(2)  =$25,000

      The time taken to make the profit is x =  2 \ years

         

From the question

     P'(x) =  xe^{-x^2}  is the rate of growth

  Now here x represent the time taken

Now the total profit is mathematically represented as

       P(x) =  \int\limits {P'(x)} \,  =   \int\limits {xe^{-x^2}} \,

So using substitution method

   We have that

                      u =  - x^2

                      du =  2xdx

  So  

        p(x) =  \int\limits {\frac{1}{2} e^{-u}} \, du

       p(x) =  {\frac{1}{2} [ e^{-u}} +c ]

       p(x) =  {\frac{1}{2}  e^{-x^2}} + \frac{1}{2} c      recall  u =  - x^2   and  let  \frac{1}{2} c =  Z

       

At  x =  2 years  

     P(x)  =$25,000

So

       Since the profit rate is in million

    P(x)  =$25,000 = \frac{25000}{1000000} =$0.025 millon dollars

So  

       0.025 =  {\frac{1}{2}  e^{-2^2}} + Z  

=>    Z = 0.025 - {\frac{1}{2}  e^{-2^2}}  

       Z = 0.016  

So the profit function becomes

         P(x) =  \frac{1}{2} e^{-x^2} +0.016

     

       

5 0
3 years ago
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