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avanturin [10]
3 years ago
15

When factored completely, m^5 + m^3 -6m is equivalent to what

Mathematics
1 answer:
Leno4ka [110]3 years ago
5 0
M(m^4+m^2-6)
This is the max you can factorize it, it cannot be factorized any further.
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Can someone help with this?
Bumek [7]
4.5/3 = x/5

then:

x = 5 * 4.5 / 3 = 15/2 = 7.5


hope that helps

6 0
4 years ago
The base of a statue of liberty is 154 feet tall.Is this number closer to 100 or 200?explain
mixer [17]
It is close to 200 because 150 or above would be rounded to 200. Below 150 would be 100
8 0
3 years ago
Read 2 more answers
Please help I'll give brainliest​
SIZIF [17.4K]

Answer:

y + 1 = 4(x - 2)

y = 4x + 11

8x - 2y = 6

Step-by-step explanation:

Following equations are parallel to the graph 4x - y = 6, because their slopes are equal (4).

y + 1 = 4(x - 2)

y = 4x + 11

8x - 2y = 6

8 0
3 years ago
The price of a watch was increased by 10% to £132. What was the price before the increase?
AnnZ [28]

Answer:120

Step-by-step explanation:

132/11= 12

it means each 10 percent is = to 12

12*10 = 120

5 0
3 years ago
Read 2 more answers
D(x)=(x^2-12x+20)/(3x)
krok68 [10]

Answers:

Vertical asymptote: x = 0

Horizontal asymptote: None

Slant asymptote: (1/3)x - 4

<u>Explanation:</u>

d(x) = \frac{x^{2}-12x+20}{3x}

      = \frac{(x-2)(x - 10)}{3x}

Discontinuities: (terms that cancel out from numerator and denominator):

Nothing cancels so there are NO discontinuities.

Vertical asymptote (denominator cannot equal zero):

3x ≠ 0  

<u>÷3</u>   <u>÷3 </u>

x ≠ 0

So asymptote is to be drawn at x = 0

Horizontal asymptote (evaluate degree of numerator and denominator):

degree of numerator (2) > degree of denominator (1)

so there is NO horizontal asymptote but slant (oblique) must be calculated.

Slant (Oblique) Asymptote (divide numerator by denominator):

  •        <u>(1/3)x - 4    </u>
  •    3x)    x² - 12x + 20
  •             <u>x²        </u>
  •                  -12x
  •                  <u>-12x         </u>
  •                             20 (stop! because there is no "x")

So, slant asymptote is to be drawn at (1/3)x - 4



6 0
3 years ago
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