Answer:
4.6
Step-by-step explanation:
![\bf ~~~~~~\textit{initial velocity} \\\\ \begin{array}{llll} ~~~~~~\textit{in feet} \\\\ h(t) = -16t^2+v_ot+h_o \end{array} \quad \begin{cases} v_o=\stackrel{64}{\textit{initial velocity of the object}}\\\\ h_o=\stackrel{0\qquad \textit{from the ground}}{\textit{initial height of the object}}\\\\ h=\stackrel{}{\textit{height of the object at "t" seconds}} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~%5Ctextit%7Binitial%20velocity%7D%20%5C%5C%5C%5C%20%5Cbegin%7Barray%7D%7Bllll%7D%20~~~~~~%5Ctextit%7Bin%20feet%7D%20%5C%5C%5C%5C%20h%28t%29%20%3D%20-16t%5E2%2Bv_ot%2Bh_o%20%5Cend%7Barray%7D%20%5Cquad%20%5Cbegin%7Bcases%7D%20v_o%3D%5Cstackrel%7B64%7D%7B%5Ctextit%7Binitial%20velocity%20of%20the%20object%7D%7D%5C%5C%5C%5C%20h_o%3D%5Cstackrel%7B0%5Cqquad%20%5Ctextit%7Bfrom%20the%20ground%7D%7D%7B%5Ctextit%7Binitial%20height%20of%20the%20object%7D%7D%5C%5C%5C%5C%20h%3D%5Cstackrel%7B%7D%7B%5Ctextit%7Bheight%20of%20the%20object%20at%20%22t%22%20seconds%7D%7D%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D)

Check the picture below, it hits the ground at 0 feet, where it came from, the ground, and when it came back down.
Answer:
part b is 32
Step-by-step explanation:
Answer:
- distance traveled: 30 m
- displacement: 21.4 m
Step-by-step explanation:
You want the distance traveled and the displacement after walking 17 m south and 13 m east.
<h3>Distance</h3>
The distance traveled is the sum of the lengths of each leg of the trip:
17 m + 13 m = 30 m
You have traveled a distance of 30 m.
<h3>Displacement</h3>
The displacement is the distance from your final position to your starting position. If you draw a diagram of the journey, you see the displacement is the hypotenuse of a right triangle with legs 17 m and 13 m. The Pythagorean theorem can help you find this length:
h = √(a² +b²)
h = √(17² +13²) = √(289 +169) = √458 ≈ 21.401
At the end of your walking, you are 21.4 m from where you started.
Answer:
is parallel to 
Step-by-step explanation:
<h3>
The complete exercise is: "Is
parallel, perpendicular or neither to 
?
"</h3><h3 />
The equation of the line in Slope-Intercept form is:

Where "m" is the slope of the line and "b" is the y-intercept.
First, in order to solve this exercise it is important to remember that, by definition:
1. The slopes of parallel lines are equal.
2. The slopes of perpendicular lines are negative reciprocal.
In this case, you have the following line given in the exercise:
You can identify that "m" and "b" are:

And the other line provided in the exercise is this one:

So, you can identify that:

As you can notice, the slopes of both lines are equal; therefore, you can conclude that those lines are parallel.