4 years ago

Can someone please help me with my homework number

Mathematics

1 answer:

icang [17]4 years ago

8 0

Answer:

Below.

Step-by-step explanation:

7. 570

8. 850

9. 820

10. 670

11. 600

12. 700

13. 700

14. 900

15. 301

16. 194

17. 487

18. 539

I hope none of these are wong, stay safe! xx

You might be interested in

Y=(x-1)^2-9 standard form

dezoksy [38]

Answer:

Y=x^2-2x-8

Step-by-step explanation:

rgbrgbrgbgbeefweuvhuuvhduvwg

6 0

3 years ago

7×6 = 42 that means that six and seven are factors of 42 true or false explain

schepotkina [342]

Answer:

Step-by-step explanation:true by multiplying 6x7=42

5 0

3 years ago

Youssef plans to get rid of cable and is comparing two high-speed internet providers. He narrows his search to two companies. Co

nadezda [96]

100 per setup fee. a.

4 0

3 years ago

In a class, 60% of the students are girls. There are 18 girls in the class.

Katarina [22]

Answer:

a. Total of 45 students.

b. 18 Boys.

5 0

3 years ago

Read 2 more answers

Use an appropriate Taylor series to find the first four nonzero terms of an infinite series that is equal to sin(5/2).

koban [17]

Answer:

2.5, -2.61, 0.81, -0.12

Step-by-step explanation:

The taylor series of the function sin(x) around zero is given by

$sin(x)=\sum_{n=0}^{\infty}\dfrac{(-1)^k}{(2k-1)!}x^{2k+1}=x-\dfrac{x^3}{3!}+\dfrac{x^5}{5!}-\dfrac{x^7}{7!}$

Therefore,

$\sin(\frac{5}{2})=\dfrac{5}{2}-\dfrac{[\frac{5}{2}]^3}{3!}+\dfrac{[\frac{5}{2}]^5}{5!}-\dfrac{[\frac{5}{2}]^7}{7!}+...$

hence the first four nonzero terms of the series are

$\dfrac{5}{2}=2.5\\\\-\dfrac{[\frac{5}{2}]^3}{3!} \approx -2.61\\\\\dfrac{[\frac{5}{2}]^5}{5!} \approx 0.81\\\\-\dfrac{[\frac{5}{2}]^7}{7!} \approx -0.12$

6 0

3 years ago