<h2>We know:</h2>
You currently make $13.50 an hour. You've earned a 15% pay raise. You want to find out your previous rate of pay per hour.
<h2>Steps:</h2>
1.) Convert 15% to a decimal, which equals 0.15
2.) Multiply your current earnings with the percentage in decimal form (0.15)
$13.50 (current pay per hour) x 0.15 (percentage in decimal form) = $2.025 (difference between your previous wage and your current wage)
3.) Subtract the difference of your previous wage and current wage with your current earnings
$13.50 (current pay per hour) - $2.025 (difference between previous and current wage) = $11.475 (previous pay per hour)
4.) Since this is talking about wage, rounding is not applicable. In other cases, your number would be rounded off to $11.48, however you can't add what you don't have, so you would have to round down.
<h2>
You were previously making $11.47 an hour.</h2>
Answer:
a)
We know that:
a, b > 0
a < b
With this, we want to prove that a^2 < b^2
Well, we start with:
a < b
If we multiply both sides by a, we get:
a*a < b*a
a^2 < b*a
now let's go back to the initial inequality.
a < b
if we now multiply both sides by b, we get:
a*b < b*b
a*b < b^2
Then we have the two inequalities:
a^2 < b*a
a*b < b^2
a*b = b*a
Then we can rewrite this as:
a^2 < b*a < b^2
This means that:
a^2 < b^2
b) Now we know that a.b > 0, and a^2 < b^2
With this, we want to prove that a < b
So let's start with:
a^2 < b^2
only with this, we can know that a*b will be between these two numbers.
Then:
a^2 < a*b < b^2
Now just divide all the sides by a or b.
if we divide all of them by a, we get:
a^2/a < a*b/a < b^2/a
a < b < b^2/a
In the first part, we have a < b, this is what we wanted to get.
Another way can be:
a^2 < b^2
divide both sides by a^2
1 < b^2/a^2
Let's apply the square root in both sides:
√1 < √( b^2/a^2)
1 < b/a
Now we multiply both sides by a:
a < b
Answer:
https://www.mathpapa.com/algebra-calculator.html
Step-by-step explanation:
Mathpapa is a pretty good and reliable algebra calculator would say to use it. It also has Inequalitys and system of equations calculators.
The answer is B as far as I know
