Answer:
0.306 in kilometers
30600 in cm
306000 in mm
3.06e+8 in micrometer
3.06e+11 in nanometer
0.19014 in mile
334.646 in yard
1003.94 in foot
12047.2 in inch
0.165227 in nautical mile
Step-by-step explanation:
Answer:
The width is 50 yards and the length is 141 yards.
Step-by-step explanation:
Let's call: L the length of the field and W the width of the field.
From the sentence, the perimeter of the rectangular playing field is 382 yards we can formulate the following equation:
2L + 2W = 382
Because the perimeter of a rectangle is the sum of two times the length with two times the width.
Then, from the sentence, the length of the field is 9 yards less than triple the width, we can formulate the following equation:
L = 3W - 9
So, replacing this last equation on the first one and solving for W, we get:
2L + 2W = 382
2(3W - 9) + 2W = 382
6W -18 +2W = 382
8W - 18 = 382
8W = 382 + 18
8W = 400
W = 400/8
W = 50
Replacing W by 50 on the following equation, we get:
L = 3W - 9
L = 3(50) - 9
L = 141
So, the width of the rectangular field is 50 yards and the length is 141 yards.
Answer:
293; 869; 11 years
Step-by-step explanation:
N: no. of frogs
t: no. of years
N = 100(1.24^t)
N = 100(1.24⁵)
= 293
N = 100(1.24¹⁰)
= 859
1000 = 100(1.24^t)
10 = 1.24^t
lg10 = t×lg1.24
t = 1/lg1.24
t = 10.7 = 11 years
The answer is 30 because a day is 24 hours so all I did was divide 720 and 24 and it gave me 30. I’m glad that I helped
Answer:
Not a subspace
Step-by-step explanation:
(4,0,0) and (0,4,0) are vectors in R3 with zero or one entries being nonzero, but their sum, (4,4,0) has two nonzero entries.
