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3 years ago

I need help with this math question for my homework.

Mathematics

2 answers:

Tasya [4]3 years ago

8 0

The answer is C: 0.786 L

Hope this helps.

Radda [10]3 years ago

4 0

Answer:

A.786,000 L

Step-by-step explanation:

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A mass of 100 g stretches a spring 20 cm. the mass is set in motion from its equilibrium position with a downward velocity of 5

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2 years ago

10 ÷ -2<br><br> What is the quotient?

Oliga [24]

The quotenet is -5 because if you divide 10 by a negitive the quotent will be negitive.

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3 years ago

Can someone help me with this and try to show the steps

anzhelika [568]

Answer:

Step-by-step explanation:

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2 years ago

Can someone please show me the steps you would use to find the value for x in the equation:

timofeeve [1]

Answer:

The answer is

7x-4=-4x+18

7x+4x=18+4

11x=22

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Step-by-step explanation:

7x-4=-4x+18

7x+4x=18+4

11x=22

x=2

7 0

3 years ago

Read 2 more answers

Use inverse functions where needed to find all solutions of the equation in the interval 2 cos2 x + 9 sin x = 6

spin [16.1K]

You can use the identity $\cos(2x) = \cos^2(x)-\sin^2(x)$ to write the equation as

$2(\cos^2(x)-\sin^2(x))+ 9\sin(x) = 6$

Now, from the fundamental equation of trigonometry, deduce an expression for $\cos^2(x)$ in terms of $\sin^2(x)$ :

$\cos^2(x)+\sin^2(x) = 1 \implies \cos^2(x) = 1-\sin^2(x)$

The equation becomes

$2(1-\sin^2(x)-\sin^2(x))+ 9\sin(x) = 6 \iff 2(1-2\sin^2(x))+ 9\sin(x) = 6$

Simplify the left hand side and move all terms to left hand side:

$2-4\sin^2(x)+ 9\sin(x) -6 = 0 \iff -4\sin^2(x) + 9\sin(x) - 4 = 0$

Now, if you let $t = \sin(x)$ , this equation becomes a quadratic equation:

$-4t^2 + 9t - 4 = 0$

The two solutions of this equations are

$t = \cfrac{9}{8} - \cfrac{\sqrt{17}}{8},\quad t = \cfrac{9}{8} + \cfrac{\sqrt{17}}{8}$

We must be careful, because we have to remember that $t$ was actually $\sin(x)$ . This means that $t$ can only assume values between -1 and 1. The second solution exceeds 1, so we reject it. So, we have

$t = \cfrac{9}{8} - \cfrac{\sqrt{17}}{8} \implies \sin(x) = \cfrac{9}{8} - \cfrac{\sqrt{17}}{8} \implies x = \arcsin\left(\cfrac{9}{8} - \cfrac{\sqrt{17}}{8}\right)$

6 0

3 years ago