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jonny [76]
4 years ago
15

Order from least to greatest 0.9,7/8,0.86

Mathematics
1 answer:
LenKa [72]4 years ago
7 0
.86,  7/8,  .9 is least to greatest
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What is the constant term in the expression 5x^2+7x+4?
Doss [256]

Answer: 4

Step-by-step explanation:

6 0
3 years ago
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PLEASE HELP!!!!!!!
andre [41]

Answer:

\frac{4^{21}}{5^6}

Step-by-step explanation:

\left(\frac{4^7}{5^2}\right)^3

=\frac{\left(4^7\right)^3}{\left(5^2\right)^3}

\left(4^7\right)^3

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\left(5^2\right)^3

5^6

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6 0
3 years ago
What is the r-value of the following data to three decimal places
Liula [17]

Answer:

option B

-0.953

Step-by-step explanation:

we know that

The<u> correlation coefficient</u> r measures the direction and strength of a linear relationship.The value of r is always between +1 and -1

Using a Excel tool (Correl function)

see the attached table

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7 0
3 years ago
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Segments AB, EF, and CD intersect at point C, and angle ACD is a right angle. Find the value of g. Please help me
iogann1982 [59]

Answer:

37 degree

Step-by-step explanation:

AB = 180 it is a straight line

ACD = 90 degree

DE+ DCB are complimentary angles they add up to 90 they dont need to be next to each other.

DE = 53 deg

DCB = 90-53= 37 degree

g = 37 and F is its vertical angle as they share the same corner point and lay opposite each other and each have same angle 37 degree.

8 0
3 years ago
Find the projection of u onto v<br> URGENT HELP
padilas [110]

Given:

Two vectors are:

u=\left

v=\left

To find:

The projection of u onto v.

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|v|=\sqrt{a^2+b^2}

Dot product of two vector v_1=\left and v_2=\left is:

v_1\cdot v_2=a_1a_2+b_1b_2

Formula for projection of u onto v is:

Proj_vu=\dfrac{u\cdot v}{|v|^2}v

Proj_vu=\dfrac{\left \cdot \left }{(\sqrt{2^2+17^2)^2}}\left

Proj_vu=\dfrac{0\cdot 2+6\cdot 17}{4+289}\left

Proj_vu=\dfrac{0+102}{293}\left

On further simplification, we get

Proj_vu=\dfrac{102}{293}\left

Proj_vu=\left

Proj_vu=\left

Therefore, the projection of u onto v is Proj_vu=\left.

3 0
3 years ago
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