Question

Write the equation for Axis of Symmetry (AOS) for: y = 2(x – 3)² + 4

Answer 1

Answer:

X=3

Step-by-step explanation:

Answer 2

The axis of symmetry is 3 because we already know the value of h and k from vertex equation also known as y=a(x-h)²+k when a≠0

If you want to know the equation of symmetry, it is -b/2a when a ≠ 0

$\frac{-b}{2a}$ But if we want to use this formula, we have to convert the vertex form into standard form.

$y=2(x^2-6x+9)+4\\y=2(x^2-6x+9)+13\\y=2x^2-12x+9+13\\y=2x^2-12x+22$

Therefore, the standard form of y=2(x-3)²+4 is 2x²-6x+22

We can use the axis of symmetry formula or -b/2a

From the equation, b is -12 and a is 2. Substitute both b and a in the -b/2a

Thus, -(-12)/2(2) = 12/4 = 3 #

Therefore, the axis of symmetry is 3. Using the Axis of Symmetry Formula, -b/2a