Solving the following inequation:
(x - 8) (x + 1) > 0
We are going to find the sign both parts of the multiplication,
(x - 8) and (x + 1), have when
x < - 8
-8 < x < 1
1 < x
Then we know (x - 8) (x + 1) > 0 whenever (x - 8) (x + 1) is positive
We can see in the figure (x - 8) (x + 1) is positive when x < -8 and x > 1
Then
Answer:B
Answer:
The coordinate of the points on the graph as shown , where ( x ,y ) = ( 3 , 2 )
Step-by-step explanation:
Given as :
The two algebraic equation is
y = 2 x - 4 .......A and y = - x + 5 ........B
The given two algebraic equation can be solved by putting the one variable to the other equation
Now , put the value of y from Eq A into the Eq B
I.e 2 x - 4 = - x + 5
or, 2 x + x = 5 + 4
or, 3 x = 9
∴ x =
I.e x = 3
So The value of x = 3
Again, put the value of x in the equation A
I.e y = 2 x - 4
or, y = 2 × 3 - 4
∴ y = 6 - 4
I.e y = 2
So The value of y = 2
So , The coordinate of points on the graph as ( x , y ) = ( 3 , 2 )
Hence The coordinate of the points on the graph as shown , where ( x ,y ) = ( 3 , 2 ) Answer
Let's assume
x represents the number of $25 tickets
y represents the number of $50 tickets
A total of 1,250 tickets
so, we get
So, cost of $25 tickets is 25x
So, cost of $50 tickets is 50y
Total cost of tickets =(cost of $25 tickets)+(cost of $50 tickets)
Total cost of tickets =25x+50y
we are given
worth $50,000, were sold
so, we get equation as
we get system of equations as
..............Answer