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dezoksy [38]
3 years ago
8

You gave $1,500 in bonuses to two employees. one employee received $200 more than the other employee. what was the amount of the

larger bonus given?
Mathematics
2 answers:
Alex787 [66]3 years ago
6 0
Let, the smaller bonus = x
Then, Larger bonus = x + 200

It is given that, x + x+200 = 1500
2x = 1500 - 200
x = 1300 / 2
x = 650
so, x + 200 = 650+200 = 850

In short, Your Answer would be $850

Hope this helps!
kotegsom [21]3 years ago
3 0
Hello there.

<span>You gave $1,500 in bonuses to two employees. one employee received $200 more than the other employee. what was the amount of the larger bonus given?

Answer: If both employees received the same amount then you would need to divide the amount by 2.
$1500 / 2 = $750.
However , in this case one employee receives $200 more than the other.
$750 + $100 = $ 850.
$750 - $100 = $650
$850 + $650 = $1500.
The larger bonus amount is $850 and the smaller is $650.

Hope This Helps You!
Good Luck Studying :)</span>
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15

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The GCF of 25 and 35, is 15

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A farmer sells 7.7 kilograms of apples and pears.3/5 of this weight is apples, and the rest is pears. How many kilograms of pear
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The weight of pears is 3.08 kg

Step-by-step explanation:

A farmer sells 7.7 kilograms of apples and pears.

3/5 of this weight is apples.

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6 0
3 years ago
A community theater uses the function p (d) = (-4d+40) (d−40) to model the profit (in dollars) expected in a weekend when the ti
fomenos

The theater make the maximum profit at d = $25. Then the maximum profit of the theatre is $ 900.

<h3>What is differentiation?</h3>

The rate of change of a function with respect to the variable is called differentiation. It may be increasing or decreasing.

A community theater uses the function P(d) = (− 4d + 40) (d − 40) to model the profit (in dollars) expected on a weekend when the tickets to a comedy show are priced at d dollars each.

Then the maximum profit of the theatre will be

The function is P(d) = (− 4d + 40) (d − 40)

Differentiate the function with respect to d and put it equal to zero for maximum or minimum profit.

\begin{aligned} \dfrac{\mathrm{d} }{\mathrm{d} d}P(d) &= 0\\\\\dfrac{\mathrm{d} }{\mathrm{d} d}(- 4d + 40) (d - 40) &= 0\\\\(-4d+40) -4 (d-40) &= 0\\\\-8d + 200 &= 0\\\\d &= 25 \end{aligned}

Then the checking for maximum or minimum, again differentiate, we have

\begin{aligned} \dfrac{\mathrm{d} }{\mathrm{d} d}P(d) &= \dfrac{\mathrm{d} }{\mathrm{d} d}(- 4d + 40) (d - 40) \\\\\dfrac{\mathrm{d} }{\mathrm{d} d}P(d) &= \dfrac{\mathrm{d} }{\mathrm{d} d}(-8d + 200) \\\\\dfrac{\mathrm{d} }{\mathrm{d} d}P(d) &= -8\\\\ \dfrac{\mathrm{d} }{\mathrm{d} d}P(d) & < 0\end{aligned}

The value is less than zero hence maximum value will occur at d = 25.

Then maximum profit will be

P(d) = (− 4×25 + 40) (25 − 40)

P(d) = (− 100 + 40) (−15)

P(d) = (− 60) (− 15)

P(d) = $ 900

More about the differentiation link is given below.

brainly.com/question/24062595

#SPJ1

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