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3 years ago

The distance from Jason’s house to school is 0.5 km what is the distance in meters

Mathematics

1 answer:

valkas [14]3 years ago

7 0

Answer:

500 meters

Step-by-step explanation:

1km=1000meters so 0.5km=500m

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Solve for x. 2x−45=x+4 Enter your answer in the box. x =

nata0808 [166]

2x - 45 = x +4

Add 45 to each side:

2x = x + 49

Subtract 1x from each side:

x = 49

7 0

3 years ago

If a function is defined by the formula y equals 2x + 1 + that domain is given by the set 3, 5, 7, 9 then which set represents t

Mariulka [41]

Answer:

{7, 11, 15, 19}

Step-by-step explanation:

The function is defined by the formula y = 2x + 1 ........ (1)

Now, domain of the function are given to be {3, 5, 7, 9}

Hence, from equation (1), at x= 3, y = 2 × 3 + 1 = 7

Now, at x = 5, y = 2 × 5 + 1 = 11

Again, at x = 7, y = 2 × 7 + 1 = 15

Finally, at x = 9, y = 2 × 9 + 1 = 19

Therefore, the range of the corresponding domain of this function is given to be {7, 11, 15, 19}. (Answer)

8 0

3 years ago

Then solve each problen

marysya [2.9K]

Answer:

a(0.80)=60

a=60/0.80

a=75

8 0

3 years ago

Two kg of tea and 3 kg of sugar cost rupees 39 in january 1997, However in march 1997 the price of the tea increased by 25% and

Irina18 [472]

Answer: tea = 15 rupees per kg

sugar= 3 rupees per kg

Step-by-step explanation:

Hi, to answer this question we have to write a system of equations with the information given:

"Two kg of tea and 3 kg of sugar cost rupees 39 in january 1997":

2 t + 3 s =39 (a)

Where:

t= price of 1 kg of tea
s = price of 1 kg of sugar

"in march 1997 the price of the tea increased by 25% (1.25)and the price of the sugar increased by 20%(1.20) and the same quantity of tea and sugar cost rupees 48.30. "

2(t1.25)+3(s1.2) = 48.30 (b)

Solving for t in (b)

2t =39-3s

t = (39 -3s)/2

t = 19.5-1.5s

Replacing the value of t in (b)

2 x ((19.5-1.5s)1.25)+ 3 ( 1.2s) =48.30

2x ( 24.375 -1.875s) +3.6s =48.30

48.75 -3.75s+3.6s= 48.30

48.75-48.30 = 3.75s-3.6s

0.45= 0.15s

0.45/0.15 =s

3 =s

Replacing the value of s in (a)

2 t + 3 (3) =39

2 t + 9 =39

2 t =39 -9

2 t =30

t = 30/2

t= 15

Prices in january:

tea = 15 rupees per kg

sugar= 3 rupees per kg

Feel free to ask for more if needed or if you did not understand something.

4 0

3 years ago

Read 2 more answers

Help asap plz ill give a gold medal. the label on cars antifreeze claims to protect the car between -30celsius and 130celsius. t

irga5000 [103]

The inequality would start out looking like this:
$-30\ \textless \ \frac{5}{9} (F-32)\ \textless \ 130$
Now it's just a matter of solving the inequalities simultaneously. Get rid of the fraction by multiplying everything by 9:
$-270\ \textless \ 5(F-32)\ \textless \ 1170$
Then distribute the 5 into the parenthesis:
$-270\ \textless \ 5F-160\ \textless \ 1170$
Now add 160 everywhere:
$-110\ \textless \ 5F\ \textless \ 1330$
and finally divide everything by 5:
-22<F<266

4 0

3 years ago