Answer:
B: (4x - 7)(16x^2 + 28x + 49)
Step-by-step explanation:
64x^3-343 can be rewritten as 4^3x^3 - 7^3 or (4x)^3 - 7^3. This is the difference of two cubes. The appropriate formula for factoring such is
a^3 - b^3 = (a - b)(a^2 + ab + b^2). Therefore,
our (4x)^3 - 7^3 = (4x - 7)(16x^2 + 28x + 49). This is Answer B.
The local minimum of function is an argument x for which the first derivative of function g(x) is equal to zero, so:
g'(x)=0
g'(x)=(x^4-5x^2+4)'=4x^3-10x=0
x(4x^2-10)=0
x=0 or 4x^2-10=0
4x^2-10=0 /4
x^2-10/4=0
x^2-5/2=0
[x-sqrt(5/2)][x+sqrt(5/2)]=0
Now we have to check wchich argument gives the minimum value from x=0, x=sqrt(5/2) and x=-sqrt(5/2).
g(0)=4
g(sqrt(5/2))=25/4-5*5/2+4=4-25/4=-9/4
g(-sqrt(5/2))=-9/4
The answer is sqrt(5/2) and -sqrt(5/2).
Answer:
Side of cube = 4 cm
Step-by-step explanation:
Given:
Volume of cube = 64 cm³
Find:
Side of cube
Computation:
Volume of cube = side³
64 = side³
Side of cube = 4 cm
9. L’(-1,-3) Z’(-5,-5) F’(-4,-2)
10. B
I think these are right if they aren’t I’m sorry
Answer:
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