1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
guajiro [1.7K]
4 years ago
7

This table shows the daily high temperature, in Fahrenheit, for two cities for ten days. City A 90 85 84 85 80 82 83 85 89 82 Ci

ty B 77 78 98 91 78 76 78 85 84 71 Which conclusion can be drawn from the data?

Mathematics
2 answers:
Anni [7]4 years ago
7 0

Since the person didn't write the answer choices they were:

A. On average, city A was warmer than city B.

B. The median and mode are different for city B.

C. The temperature range between the maximum and minimum values for city A is greater than the temperature range between the maximum and minimum values for city B.

D. The median is less for city A than for city B.

I believe it is A personally cause i took the test and got it right

Artist 52 [7]4 years ago
7 0

Answer:

  1. On average city A is warmer than city B
  2. The median and mode are same for city B.
  3. The temperature range between the maximum and minimum values for city B is greater than the temperature range between the maximum and minimum values for city A.
  4. The median is less for city B than for city A.                

Step-by-step explanation:

We are given the following information in the question:

City A: 90  85  84  85  80  82  83  85  89  82

City B:  77  78  98  91  78  76  78  85  84  71

Formula:

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}

Mode is the most frequent observation

City A:

Mean =\displaystyle\frac{845}{10} = 84.5

Median:

Sorted data: 80, 82, 82, 83, 84, 85, 85, 85, 89, 90

Median = \frac{84+85}{2} = 84.5

Mode = 85

Minimum = 80

Maximum = 90

Range = Maximum - Minimum = 10

City B:

Mean =\displaystyle\frac{816}{10} = 81.6

Median:

Sorted data: 71, 76, 77, 78, 78, 78, 84, 85, 91, 98

Median = \frac{78+78}{2} = 78

Mode = 78

Minimum = 71

Maximum = 98

Range = Maximum - Minimum = 27

Thus, we can say that:

  • On average city A is warmer than city B
  • The median and mode are same for city B.
  • The temperature range between the maximum and minimum values for city B is greater than the temperature range between the maximum and minimum values for city A.
  • The median is less for city B than for city A.
You might be interested in
Which measurement is the same length as 1 meter
dedylja [7]

Answer:

3 feet

Step-by-step explanation:

5 0
3 years ago
Plz help me quick.....................................................
charle [14.2K]

Answer:

-2

Step-by-step explanation:

The equation is -12/c=6

by solving for c you get,

-12/c=6

Then multiply both sides by the LCM c to get, -12=6c

Divide both sides by 6 to get,

-12/6=6c/6

-2=c

Verification:

-12/-2=6 since when a negative number divides a negative number the answer is a positive value

7 0
3 years ago
Simplify √5(10-4√2)<br><br> A.14<br> B.15√2<br> C.5√2-4√10<br> D.NONE OF THE ABOVE
Rudiy27
√5 (10-4√2)
=10√5-4√10

The answer is D
5 0
3 years ago
Read 2 more answers
EASY MATH!!! The formula F=9/5C+32 is used to convert Celsius to Fahrenheit temperature. A. Solve the formula for C B. The boili
puteri [66]

F=\dfrac{9}{5}C+32\\\\A.\\\dfrac{9}{5}C+32=F\ \ \ |-32\\\\\dfrac{9}{5}C=F-32\ \ \ |\cdot\dfrac{5}{9}\\\\C=\dfrac{5}{9}(F-32)



B.\\F=212\to C=\dfrac{5}{9}(212-32)=\dfrac{5}{9}\cdot180=100\\\\212^oF=100^oC



C.\\F=80\to C=\dfrac{5}{9}(80-32)=\dfrac{5}{9}\cdot48\approx26.7\\\\80^oF\approx26.7^oC

4 0
3 years ago
You are setting up a zip line in your yard. You map out your yard in a coordinate plane. An equation of the line representing th
neonofarm [45]

Answer:

Distance is 6.7units to the nearest tenth.

Explanation:

To solve this problem, we the distance formula. And this is given as:

D = \frac{|a x + b y + c|}{\sqrt{a^2 + b^2}}

We were given the equation:

y = 2 x + 4

This can also be rewritten as:

y – 2 x – 4 = 0.

Therefore, a = -2, b = 1 and c = -4

Also, we were given the points:

(x, y) = (–4, 11)

Making use of the above formula for distance, we have:

D = \frac{|-2\times -4 + 1\times 11 + -4|}{\sqrt{-2^2 + -4^2}}

D = \frac{15}{\sqrt{5}}

D = 6.7units (to the nearest tenth)

8 0
3 years ago
Other questions:
  • For a circle of radius 9 feet, find the arc length s cut off by a central angle of 6°
    6·1 answer
  • Add using a number line 5/6 plus - 1 1/6
    7·1 answer
  • Compare the number of x intercepts in the graph f(x)=x2 to the number of x intercepts in the graph of g(x)=x2-7. Be sure to incl
    8·1 answer
  • in 1960 there were approximately 3,000 million people on earth, in 1999 there were 6,000 people on earth what was the approximat
    11·1 answer
  • what is the different of the perimeter of the rectangle if its width has been increase by 7 and its length increase by 5
    13·2 answers
  • A grasshopper has a length of (5x - 2) inches. A spider has a length of (2x - 1) inches. How much longer is the grasshopper?
    10·1 answer
  • Peyton’s field hockey team wins 4 games out of every 7 games played. Her team lost 9 games. Set-up and solve a proportion that f
    5·1 answer
  • Write an equivalent system of equations to the following of equations: 2x+2y=-6 and x-4y=2​
    7·1 answer
  • a linear function contains the following points. what are the slope and y-intercept of this function?
    14·1 answer
  • Perimeter?<br> 2cm<br> 55mm<br> 10cm<br> 60mm
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!