Answer:
The triangle is both an Isosceles triangle and a right triangle.
Step-by-step explanation:
Given the vertices of a triangle.

and

We find the distance between all the points to determine the length of each side of the triangle.
Distance between any two points, say,
and
is:

Length between
and
, (Side 1) :
and

Distance = 


Length of Side 1 =
units.
Distance between
and
, (Side 2):


Distance = 


Length of Side 2 =
units.
Distance between
and
, Side 3 :

Distance = 


Length of Side 3 =
units.
Note that the length of Side 1 = Length of Side 3.
That means the triangle is Isosceles.
Also, For a triangle to be right angle triangle, using Pythagoras theorem we have:
(Side 1)² + (Side 3)² = (Side 2)²

i.e, 53 + 53 = 106
Hence, the triangle is a right - angled triangle as well.