About 96 becuse in one liter there is four 8 oz glases so that makes 32 and if you add 32 three times you get 96
The domain of the function is [-4, 4) and the range of the function is [-5, 2)
<h3>How to determine the domain and the range of the function?</h3>
<u>The domain</u>
As a general rule, it should be noted that the domain of a function is the set of input values or independent values the function can take.
This means that the domain is the set of x values
From the graph, we have the following intervals on the x-axis
x = -4 (closed circle)
x =4 (open circle)
This means that the domain of the function is [-4, 4)
<u>The range</u>
As a general rule, it should be noted that the range of a function is the set of output values or dependent values the function can produce.
This means that the range is the set of y values
From the graph, we have the following intervals on the y-axis
y = -5 (closed circle)
y = 2 (open circle)
This means that the range of the function is [-5, 2)
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It will take 0.4 seconds to get to the home plate.
Given:
The speed of the pitch thrown by Justin is 100 miles per hour
The distance of home plate from the pitching rubber is 60.5 feet
To find:
The time taken by a pitch to reach the home plate
Solution:
The distance home plate from the pitching rubber = d = 60.5 feet

The speed of pitch thrown by Justin = s = 100 miles/hr
The time taken by a pitch to reach the home plate = t =?
The speed of the moving object is given by dividing the distance covered from the time taken to cover that distance.

In an hour there are 3600 seconds, then in 0.000114583 hours will be:

It will take 0.4 seconds to get to the home plate.
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Answer:
3040
Step-by-step explanation:
given arithmetic progression is
70,100,130,...
here
first term (a)=70
common difference (d)=100-70=30
number of term n=100
using the formula of arithmetic progression
an=a+(n-1)d
a100=70+(100-1)30
a100=70+99×30
a100=70+2970
a100=3040
Answer:
-7 - 3a = 1 – 4a
Step one: Add 4a to -3a
-7 + a = 1
Step two: Add 7 to 1
A = 8
You're done! A=8 for this problem!
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