The correct structure of the question is as follows:
The function f(x) = x^3 describes a cube's volume, f(x) in cubic inches, whose length, width, and height each measures x inches. If x is changing, find the (instantaneous) rate of change of the volume with respect to x at the moment when x = 3 inches.
Answer:
Step-by-step explanation:
Given that:
f(x) = x^3
Then;
V = x^3
The rate whereby V is changing with respect to time is can be determined by taking the differentiation of V
dV/dx = 3x^2
Now, at the moment when x = 3;
dV/dx = 3(3)^2
dV/dx = 3(9)
dV/dx = 27 cubic inch per inch
Suppose it is at the moment when x = 9
Then;
dV/dx = 3(9)^2
dV/dx = 3(81)
dV/dx = 243 cubic inch per inch
Answer:
5.83095 or √34
Step-by-step explanation:
Find the difference between coordinates:
(x2-x1) = (-1 - -4) = 3
(y2-y1) = (-10 - -5) = -5
Square the results and sum them up:
(3)2 + (-5)2 = 9 + 25 = 34
Now Find the square root and that's your result:
Exact solution: √34 = √34
Approximate solution: 5.831
Answer:
2x-7
Step-by-step explanation:
