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3 years ago

I need to estimate help me pls

Mathematics

1 answer:

cricket20 [7]3 years ago

4 0

The answer would be H-orange juice

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Which statements are true about the ordered pair (-1,-4) and the system of equations?

JulijaS [17]

Answer:

When (-1,-4) is substituted into the first equation, the equation is true.

When (-1,-4) is substituted into the second equation, the equation is true.

Step-by-step explanation:

The given system is

x-y=3

7x-y=-3

Make x the subject in the top equation to get:

x=y+3

Put x=y+3 in the bottom equation to get:

7(y+3)-y=-3

Expand

7y+21-y=-3

7y-y=-3-21

6y=-24

y=-4

Put y=-4 into x=y+3 to get

x=-4+3=-1

Hence the point (-1,-4) is a solution to both equation

5 0

4 years ago

For what number of minutes will Plan A and Plan B cost the same

natita [175]

Plan B will work for 3 days multiplied by 24 hours (:

8 0

3 years ago

James is driving his car.He is sitting at a stop light at rest. When the light turns green, he accelerates to 18m/s in 10 second

Alexus [3.1K]

Answer:

His acceleration is 1.8m/s²

Step-by-step explanation:

acceleration, a = velocity, v / time, t

Velocity = 18m/s, unit is in m/s

time = 10 seconds, unit is in s

Therefore, a = 18m/s/10s = 1.8m/s²

5 0

3 years ago

What is the common ratio for the geometric sequence 3,12,48,192

My name is Ann [436]

Okay, so try dividing a2 from a1 (to find geometric ratio, divide a2 from a1 :) )
12 ÷ 3 = 4
See if the other numbers have the same geometric ratio.
48 ÷ 12 = 4
192 ÷ 48 = 4
The common ratio is 4.

7 0

3 years ago

Read 2 more answers

The number of hours worked per year per person in a state is normally distributed with a standard deviation of 39. A sample of 1

evablogger [386]

Answer:

The 98% confidence interval for the population mean number of hours worked per year per person is (2146, 2193).

Step-by-step explanation:

The question is incomplete.

The number of hours registered in the sample are:

2051 2061 2162 2167 2169 2171

2180 2183 2186 2195 2196 2198

2205 2210 2211

The sample mean can be calculated as:

$M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{15}(2051+2061+2162+2167+2169+2171+2180+2183+2186+2195+2196+2198+2205+2210+2211)\\\\\\M=\dfrac{32545}{15}\\\\\\M=2169.67\\\\\\$