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kobusy [5.1K]
3 years ago
6

What is the sum? 8 + (negative 12) –20 –4 4 20

Mathematics
2 answers:
brilliants [131]3 years ago
6 0

Answer:

-4

Step-by-step explanation:

Romashka-Z-Leto [24]3 years ago
3 0

8 + (-12)

= 8 - 12

= -4

Because a + - makes a -

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Simplify a-c when a=5 c= -1​
nordsb [41]
5- -1= 6


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8 0
3 years ago
Read 2 more answers
What are the solutions to m2 - 9 = 0?
kolezko [41]

Answer:

m=3 and m=-3

Step-by-step explanation:

m^2 = 9

m = square root of 9

Since a positive or negative number squared produce a positive value, the answer is either positive or negative.

3 0
3 years ago
The legs of a right triangle are 2 and 3. Find the exact value (no decimals) of the hypotenuse.
AVprozaik [17]
A^2 +b^2 =c^2
2^2 + 3^2
4+9=13
The hypotenuse is equal to the square root of 13
5 0
3 years ago
Bobby and Rick are in a 16​-lap race on a​ one-mile oval track.​ Bobby, averaging 94 ​mph, has completed six laps just as Rick i
Reptile [31]

Answer: Hello!

first let's note the things we already know:

there is a 16- lap race and the oval has one mile of length, then each of the laps has a length of one mile, and the whole race has 16 miles in total

Bobby averages 94 mph and already did 6 laps ( or 6 miles)

then we could write the Bobby equation as B(t) = 6 miles + 94mph*t

where t represents the time in hours.

now we could see how much time Bobby needs to end the race:

B(x) = 6mi + 94mph*x = 16mi

94mph*x = 16mi - 6mi = 10mi

x = (10/94)h = 0.106h

so Bobby needs 0.106 hours to finish the race, and we want to know which velocity Rick should have in order to reach the end of the race at the same time as Bobby.

Rick is starting the race, so he needs to do 16 miles in 0.106 hours, and as we know velocity is distance over time; so the average velocity of Rick is:

V = 16mi/0.106h = 150.9mph

Now let's see the hint:

Bobby does 8 miles in:

94*t = 8

t = 8/94 = 0.085 hours

and Rick does 10 miles in:

150.9*t = 10

t = 10/150.9 = 0.066 hours

wich is clearly different times, so maybe the hint is wrong.

5 0
3 years ago
The difference of the square of a number and 4 is equal to 3 times that number. Find the negative solution.
leonid [27]

The negative solution is x = –1.

Solution:

Let the number be x.

Square of a number = x²

3 times a number = 3x

Difference of square of a number and 4 = 3 times that number

\Rightarrow x^2-4=3x

Subtract 3x from both sides of the equation, we get

\Rightarrow x^2-3x-4=0

–3x can be written as x – 4x.

\Rightarrow x^2+x-4x-4=0

\Rightarrow( x^2+x)+(-4x-4)=0

1st bracket have common term x and bracket have –4 common term.

\Rightarrow x( x+1)-4(x+1)=0

Take common term x + 1 outside.

(x+1)(x-4)=0

<em>By zero factor principle, if AB = 0 then A = 0 or B = 0.</em>

x + 1 = 0,   x – 4 = 0

x = –1,   x = 4

The negative solution is x = –1.

7 0
3 years ago
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