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AURORKA [14]
3 years ago
5

CAN SOMEONE HELP PLZ

Mathematics
1 answer:
Vlad1618 [11]3 years ago
7 0

Answer:

Step-by-step explanation:

1)

The solution to the system (c , p) represent the cost of each hot cocoa is c and the cost of each pretzel is p

2)

Nothing changed just two equations were added to form another third equation which represent the total cost of 7 cups of hot cocoa and 8 pretzels

so the solution (c , p) would still be the same as the solution represents cost of each cup of hot cocoa c and cost of each pretzel p

3)

No adding both the equations does not help us solve the equation, It just forms another equation further making the question longer and the third equation is not needed because to solve a system of equations with 2 variables to equations are enough, in this case c and p To solve the system of equations we multiply the first equation with 2 and the second equation with 5 and then subtract equation 1 from equation 2

Equation\ 1 \\\\5c+4p=18.40\\Multiplying\ it\ with\ 2\\10c+8p=36.8\\\\Equation\ 2\\\\2c+4p=11.20\\Multiplying\ equation\ 2\ with\ 5\\10c+20p=56\\\\Now\ subtract\ equation\ 2\ from\ equation\ 1\\\\10c-10c+8p-20p=36.8-56\\0-12p=-19.2\\-12p=-19.2\\p=-19.2/-12\\p=1.6\\

Now for the value of c we insert the value of p in any equation, lets insert it in equation 1

5c+4p=18.40\\5c+4(1.6)=18.40\\5c+6.4=18.40\\5c=12\\c=12/5\\c=2.4

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The volume of a sphere is decreasing at a constant rate of 116 cubic centimeters per second. At the instant when the volume of t
nirvana33 [79]

Answer:

\frac{dr}{dt}  = -1.325 \ cm/s

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Calculus</u>

Derivatives

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Taking Derivatives with respect to time

Step-by-step explanation:

<u>Step 1: Define</u>

Given:

<u />V = \frac{4}{3} \pi r^3<u />

<u />\frac{dV}{dt} = -116 \ cm^3/s<u />

<u />V = 77 \ cm^3<u />

<u />

<u>Step 2: Solve for </u><em><u>r</u></em>

  1. Substitute:                    77 = \frac{4}{3} \pi r^3
  2. Isolate <em>r</em> term:               \frac{77}{\frac{4}{3} \pi} = r^3
  3. Isolate <em>r</em>:                        \sqrt[3]{\frac{77}{\frac{4}{3} \pi}}  = r
  4. Evaluate:                       2.63917  = r
  5. Rewrite:                         r = 2.63917 \ cm

<u>Step 3: Differentiate</u>

<em>Differentiate the Volume Formula with respect to time t.</em>

  1. Define:                                                                                                            V = \frac{4}{3} \pi r^3
  2. Differentiate [Basic Power Rule]:                                                                   \frac{dV}{dt}  = \frac{4}{3} \pi \cdot 3 \cdot r^{3-1} \cdot \frac{dr}{dt}
  3. Simplify:                                                                                                           \frac{dV}{dt}  = 4 \pi r^2 \cdot \frac{dr}{dt}

<u>Step 4: Find radius rate</u>

  1. Substitute in variables:                    -116 \ cm^3/sec  = 4 \pi (2.63917 \ cm)^2 \cdot \frac{dr}{dt}
  2. Isolate dr/dt rate:                             \frac{-116 \ cm^3/s}{4 \pi (2.63917 \ cm)^2} = \frac{dr}{dt}
  3. Evaluate:                                          -1.3253 \ cm/s = \frac{dr}{dt}
  4. Rewrite:                                           \frac{dr}{dt}  = -1.3253 \ cm/s
  5. Round:                                             \frac{dr}{dt}  = -1.325 \ cm/s

Our radius is decreasing at a rate of -1.325 cm per second.

6 0
3 years ago
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