9514 1404 393
Answer:
(x^(1/2))(x^(1/2)) = x^(1/2 +1/2) = x^1 = x
Step-by-step explanation:
The rule of exponents is ...
(x^a)(x^b) = x^(a+b)
From which ...
(x^a)(x^a) = x^(a+a) = x^(2a)
So, if we want two identical factors that have a product of x = x^1, then the exponents of those factors will be such that ...
x^(2a) = x^1
2a = 1
a = 1/2
The square root is defined as one of two identical factors that have a product equal to the specified value. That is ...
(√x)(√x) = x
Above, we have shown that ...
(x^(1/2))(x^(1/2)) = x
so, we can conclude ...
√x = x^(1/2)
_____
<em>Additional comment</em>
In like fashion, we can show that the n-th root of a number is the same as that number to the 1/n power. It's really a matter of definition. Since the square of x^(1/2) is x, we call x^(1/2) the square root. It is used commonly enough that it has its own symbol: √x.
Answer:
A. the domain is all real numbers. and
B.the y-intercept is 3
Answer:
What are you asking for us to solve? the Inverse Operation, Exact Value, Simplify and etc
Step-by-step explanation:
A picture would be nice please.
Answer:
We use log to solve only those equations in which we have our variables in power form.
Step-by-step explanation:
Given : Margee thinks she can use logs to solve 
, since logs seem to make exponents disappear but Margee is wrong
We have to explain the difference between equations like 
and
We use log to solve only those equations in which we have our variables in power form.
Out of given equation only has x in power form so we can apply log for solving the equation as,
While solving other equation ,
, we can directly take 8 root both side, 
Thus, We use log to solve only those equations in which we have our variables in power form.
Rational because it can be expressed as a fraction.
