Answer: a) An = An-1 + An-2
b) 55ways
Step-by-step explanation:
a) a nickel is 5 cents and a dime is 10cent so a multiple of 5 cents is the possible way to pay the tolls in both choices.
Let An represents the number of possible ways the driver can pay a toll of 5n cents, so that
An = 5n cents
Case 1: Using a nickel for payment which is 5 cents, the number of ways given as;
An-1 = 5( n-1)
Case 2: using a dime which is two 5 cents, the number of ways is given as;
An-2 = 5(n-2)
Summing up the number of ways, we have
An = An-1 + An-2
From the relation,
If n= 0, Ao= 1
n =1, A1= 1
b) 45 cents paid in multiples of 5cents will give us 9 ways(A9)
From the relation, we have that
Ao = 1
A1 = 1
An =An-1 + An-2
Ao = 1
A1 = 1
A2 = A1+Ao = 1+1= 2
A3 = A2 + A1 = 3
A4 = A3+A2=5
A5=A4+A3=8
A6=A5+A4=13
A7 =A6+A5 = 21
A8= A7+A6= 34
A9= A8+A7= 55
So there are 55ways to pay 45cents.
Answer:
n = -6
Step-by-step explanation:
2 ( n + 5 ) = -2
First, solve the brackets.
2n + 10 = -2
Now take 10 to the right side.
2n + 10 -10 = -2 - 10
2n = -12
Then divide both sides by 2.
And now you'll the value of n.
n = ( -6 )
Si 1,2,4,5,8,10,16,20,40,80
That's not a squre
anyway, we use ratios
base:person to corner=28:8
height to height=x:5
so
28/8=x/5 becasue same ratio
28/8=14/4=7/2
7/2=x/5
multiply
35/10=2x/10
35=2x
divide 2
17.5=x
x=17.5 feet
