We have been given that point a is at 
and point c is at 
. We are asked to find the coordinates of point b on segment ac such that the ratio is 1:3.
We will use section formula to solve our given problem.
When point P divides a segment internally in the ratio m:n, the coordinates of point P would be:
![[x=\frac{mx_2+nx_1}{m+n}, y=\frac{my_2+ny_1}{m+n}]](https://tex.z-dn.net/?f=%5Bx%3D%5Cfrac%7Bmx_2%2Bnx_1%7D%7Bm%2Bn%7D%2C%20y%3D%5Cfrac%7Bmy_2%2Bny_1%7D%7Bm%2Bn%7D%5D)
Let point 
and point 
.
![[x=\frac{1(4)+3(-2)}{1+3}, y=\frac{1(7)+3(4)}{1+3}]](https://tex.z-dn.net/?f=%5Bx%3D%5Cfrac%7B1%284%29%2B3%28-2%29%7D%7B1%2B3%7D%2C%20y%3D%5Cfrac%7B1%287%29%2B3%284%29%7D%7B1%2B3%7D%5D)
![[x=\frac{4-6}{4}, y=\frac{7+12}{4}]](https://tex.z-dn.net/?f=%5Bx%3D%5Cfrac%7B4-6%7D%7B4%7D%2C%20y%3D%5Cfrac%7B7%2B12%7D%7B4%7D%5D)
![[x=\frac{-2}{4}, y=\frac{19}{4}]](https://tex.z-dn.net/?f=%5Bx%3D%5Cfrac%7B-2%7D%7B4%7D%2C%20y%3D%5Cfrac%7B19%7D%7B4%7D%5D)
![[x=-0.5, y=4.75]](https://tex.z-dn.net/?f=%5Bx%3D-0.5%2C%20y%3D4.75%5D)
Therefore, the coordinates of point 'b' would be 
.
I think it is "More teens play soccer than any other sport"
Answer:
Number of milk chocolate in beg = 56
Step-by-step explanation:
Given:
Probability of randomly choosing a dark chocolate = 3/8
Number of dark chocolate = 21
Find:
Number of milk chocolate in beg
Computation:
Number of milk chocolate in beg = Number of dark chocolate / Probability of randomly choosing a dark chocolate
Number of milk chocolate in beg = 21 / [3/8]
Number of milk chocolate in beg = 21[8/3]
Number of milk chocolate in beg = 7[8]
Number of milk chocolate in beg = 56
Answer:
0.6
Step-by-step explanation:
In this question, the | symbol means "given", so we can phrase the question as "Find the probability that a student watches more than one hour of TV given that they are in the 6th period class"
Next, because there is a 100% chance that the student is in the 6th period class, we can disregard the results of the 3rd period class.
Given that the student is in the 6th period class, there are 15 total students (as 9+6=15 = the sum of the yes and no answers for 6th period) and 9 students that said yes. Therefore, there is a 9/15 = 3/5 = 0.6 probability that a student watches more than 1 hour of TV given that they are in the 6th period class
Not really sure i think its b not sure
