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3 years ago

PLEASE HELP ME I WILL MARK BRAINLIEST!!!

Mathematics

1 answer:

OLEGan [10]3 years ago

5 0

Answer:

v= 205.3

Step-by-step explanation:

The formula to solve a pyramid is v=(l*h*w)/3.

11*7*8=616

616/3=205.333.... (repeating 3)

about 205.3

~sorry I couldn't draw it out~

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2c - 4p> -6 and 3c + 1 < 13

mel-nik [20]

what do you have to do???

5 0

3 years ago

PLEASE HELP ME!! I WILL MARK THE FIRST CORRECT ANSWER BEAINLIEST!!))

sergey [27]

Answer:

7598.80

Step-by-step explanation:

V=πr^2h

= 3.14 * 11^2 * 20

= 2420π or 7598.80

6 0

2 years ago

Read 2 more answers

Giselle works as a carpenter and as a blacksmith. She earns $ 2 0 $20dollar sign, 20 per hour as a carpenter and $ 2 5 $25dollar

dem82 [27]

She worked as a carpenter for 12 hours and as a blacksmith for 18 hours.

Assuming you mean she earned $20 as a carpenter and $25 as a blacksmith per hour, with a total of 30 hours for $690,
let c represent carpenter hours and b for blacksmith hours.

20c + 25b = 690
c + b = 30
Subtract b from each side so that c = 30 - b
Plug this value into the first equation

20(30 - b) + 25b = 690
600 - 20b + 25b = 690
600 + 5b = 690
5b = 90
b = 18

To find c, plug this value of b into the other equation
c + 18 = 30
c = 12

3 0

3 years ago

Read 2 more answers

I need help (20 points)

Illusion [34]

Answer:

no they are not perpendicular

3 0

3 years ago

You spin each spinner once. On the spinners, R represents red, B represents blue, G represents green, Y represents yellow, and P

NeTakaya

Answer:

1/6

1/12

1/2

Step-by-step explanation:

There are three possible outcomes in the left spinner, and four possible outcomes in the right spinner. So there are a total of 3×4=12 possible combinations. We can show that by making a grid:

$\left[\begin{array}{cccc}&R&B&G\\R&RR&BR&GR\\B&BR&BB&BG\\P&PR&BP&GP\\Y&RY&BY&GY\end{array}\right]$

Of these 12 combinations, 2 show both spinners landing on the same color (RR and BB). So the probability is 2/12 = 1/6.

There is only 1 outcome in which the first spinner lands on R <em>and</em> the second spinner lands on P (PR), so the probability is 1/12.

There are 6 outcomes in which the first spinner lands on R <em>or</em> the second spinner lands on P (RR, BR, PR, RY, BP, GP). So the probability is 6/12 = 1/2.

7 0

3 years ago