A/2-b/3=1 solve for a, add b/3 to both sides
a/2=1+b/3 which is equal to
a/2=(3+b)/3 multiply both sides by 2
a=(6+2b)/3 now you can substitute this into 2a+3b giving you:
2(6+2b)/3 + 3b which is equal to
(12+4b+9b)/3
(13b+12)/3
Answer:
r≥0
V(r) ≥0
Step-by-step explanation:
V(r) = 4/3 * Pi* r^3
The domain is the input values for r
The radius cannot be less than 0 but can be any number bigger than 0
What is the domain of the function in this situation?
r≥0
The range is the output values for the function or the volume
The volume must be greater than or equal to zero
V(r) ≥0
try and see if it =0
Step-by-step explanation:
This deals with factoring multi-variable polynomials.
Answer:
464
Step-by-step explanation:
answer:
b6
step bye step?
soalnya itu dibagi w = b6 maaf kalo salah wkwk
