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2 years ago

The marginal cost function of producing q mountain bikes is 600/0.3q+5.

1 answer:

4 0

MArginal cost is the adjustment in all out cost that emerges when the amount created changes by one unit.(In another word subordinate of cost wrt unit)
So we coordinate to get Cost work
∫30 600/0.3q+5 (dq) 0
we get 9798.66 from joining.
We add that to settle cost 2059.23+2200=4259.24
So 4259.24 is the cost.
Income from offering the bicycle is 205*30=6150
and Profit=Revenue-Cost
6150 - 4259.24=1890.76
Presently Marginal Profit
MArginal benefit is the term used to allude to the contrast between the minor cost the peripheral income for delivering one extra unit of creation.
Marginal Profit=Marginal Revenue-Marginal Cost
Marginal Cost=600/0.3q+5.
We should connect to 31 to get 41.958
Revenue= 205q

Marginal rev=205
Marginal Profit = 205-41.958=163.042

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What is $5.60 for 4 pounds as a unit rate.

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2 years ago

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Step-by-step explanation:

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3 years ago

If the class contains 11 boys and 14 girls, what is the probability of calling on a girl?

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Answer: P (girl) = 14 / 25

Concept:

Here, we need to know the idea of probability.

Probability is a measure of the likelihood of an event to occur.

If you are still confused, please refer to the attachment below for a graphical explanation.

Solve:

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Number of girls = 14

Total number of people = 11 + 14 = 25

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P (girl) = 14 / 25

Hope this helps!! :)

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3 years ago

Consider the graph of the line y = x – 4 and the point (−4, 2).

Hitman42 [59]

Answer:

a. The slope of a line parallel to the given line is 1

b. A point on the line parallel to the given line, passing through (−4, 2), is (1,7)

c. The slope of the line perpendicular to the given line is -1

d. A point on the line perpendicular to the given line, passing through (−4, 2), is (3,-5)

Step-by-step explanation:

The equation of the line in Slope-intercept form is:

$y=mx+b$

Where m is the slope and b is the y-intercept.

a. For the line $y = x - 4$

You can identify that:

$m=1$

By definition, two lines are parallel if they have the same slope. Then, the slope of a line parallel to the given line is:

$m=1$

b. The equation of the line in Point-slope form is:

$y -y_1 = m(x - x_1)$

Where m is the slope and ( $x_1,y_1$ ) is a point of the line.

Given the point (-4,2), substitute this point and the slope of the line into the equation:

$y -2 = (x +4)$

Give a value to "x", substitute it into this equation and solve for "y":

For $x=1$ :

$y -2 = (1 +4)$

$y= 5+2$

$y= 7$

Then, you get the point (1,7)

c. The slopes of perpendicular lines are negative reciprocals, then the slope of a line perpendicular to the given line is:

$m=-\frac{1}{1}\\\\m=-1$

d. Given the point (-4,2), substitute this point and the slope of the line into the equation:

$y -2 = -1(x +4)$

$y -2 = -(x +4)$

Give a value to "x", substitute it into this equation and solve for "y":

For $x=3$ :

$y -2 = -(3 +4)$

$y= -7+2$

$y= -5$

Then, you get the point (3,-5)

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3 years ago