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MakcuM [25]
3 years ago
13

This trip covers approximately 1,500 miles. You plan to return the car with a full tank of gasoline. You are considering two opt

ions advertised by Hertz: Toyota Camry, 33 mpg highway, costs $465.59 plus taxes and fees totaling $553.28. Toyota Prius Hybrid, 48 mpg highway, costs $634.49 plus taxes and fees totaling $804.61. In both cases, you must purchase gasoline, which costs approximately $3.80 per gallon in California.
Mathematics
1 answer:
solmaris [256]3 years ago
3 0
<span>This answer assumes that the majority of the 1,500 miles are on the highway. After adding up the total cost for the trip for each car, the Toyota Camry is the better value. Toyota Camry: Base Price: $553.28 Gas Price: $172.72 Total Price: $726.01 Toyota Prius: Base Price: $804.61 Gas Price: $118,75 Total Price: $923.36 Therefore, based on the distance traveled on this trip, the Toyota Camry is the better value. A longer trip would likely turn the Prius into the better value but not for a 1,500 mile trip.</span>
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Step-by-step explanation:

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6 0
3 years ago
An aptitude test has a mean score of 80 and a standard deviation of 5. The population of scores is normally distributed. What pr
konstantin123 [22]

Answer:

2.28% of tests has scores over 90.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 80, \sigma = 5

What proportion of tests has scores over 90?

This proportion is 1 subtracted by the pvalue of Z when X = 90. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{90 - 80}{5}

Z = 2

Z = 2 has a pvalue of 0.9772.

So 1-0.9772 = 0.0228 = 2.28% of tests has scores over 90.

8 0
3 years ago
How do you solve for y?
ss7ja [257]
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