Jackson sold 27 pounds of bananas and 12 pounds of grapes.
Given that Jackson runs a farm stand that sells bananas and grapes, and each pound of bananas sells for $ 1 and each pound of grapes sells for $ 2.25, and Jackson sold 15 more pounds of bananas than pounds of grapes and made $ 54 altogether, to determine the number of pounds of bananas sold and the number of pounds of grapes sold the following calculation must be performed:
- 25 x 1 + 10 x 2.25 = 25 + 22.50 = 47.50
- 26 x 1 + 11 x 2.25 = 26 + 24.75 = 50.75
- 27 x 1 + 12 x 2.25 = 27 + 27 = 54
Therefore, Jackson sold 27 pounds of bananas and 12 pounds of grapes.
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Here you go. Do you think that you could help me with my question
5a – 10b = 45
5a – 10(3) = 45
5a – 30 = 45
+30 +30
5a = 75/5
<span>a = 15</span>
One could be |x|<-2
This could be one since no matter what you put in for x, it will always be positive.
Answer:
(1) .20 (2) .40 (3) .12 (4) Less than
Step-by-step explanation:
You have to look at the table. There are 5 columns with 10 rows. 5x10=50
Then simply count the boxes that have the correct number of currency for instance, if they are asking for EXACTLY 1 dime then you rule out the ones that have 2 or 3 dimes and only the count the ones that have a single dime. So you count PDN but you would not count PDD. There are 20 boxes that have a single dime in them. 20 out of the 50 boxes. 20/50=.40 (answer 2)
The estimated probability that exactly two of the three coins Avery randomly picked are nickels is .
20
The estimated probability that exactly one of the three coins Avery randomly picked is a dime is .
40
The estimated probability that all three coins Avery randomly picked are pennies is .
12
The answer to #1 is .20 or 20% and the answer to #2 is .40 or 40%. 20% is less than 40% so...
The estimated probability that exactly two of the three coins Avery randomly picked are nickels is LESS THAN the estimated probability that exactly one of the three coins Avery randomly picked is a dime.
It is in all 0.0098934551 in all in total