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Answer:
19,656
Step-by-step explanation:
Numbers used in locker = 3
Total numbers available = 28
Repetition is not allowed, so one number can be used only once. The order of number matters in the locker e.g. 123 password is not the same as 231. Since, the order of numbers matter, this is a problem of permutations. We need to find the number of different sequences formed with 28 numbers taken 3 at a time. This can be represented as 28P3
The formula for permutations is:

For the given case, we will have:

This means, 19,656 different 3 numbered sequences are possible for the locker.
Answer:
∠B ≈ 30.0°
Step-by-step explanation:
The law of sines can be used to solve a triangle when two sides and an angle opposite one of them are given.
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sin(B)/b = sin(C)/c
sin(B) = (b/c)sin(C) . . . . solve for sin(B)
sin(B) = (14/28)sin(91°) ≈ 0.49992385
The angle is found using the inverse sine function:
B = arcsin(0.49992384) ≈ 29.99496°
Rounded to tenths, the angle is ...
m∠B ≈ 30.0°
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<em>Additional comments</em>
Many triangle solver apps and web sites are available if all you want is an answer.
When using your calculator, be sure the angle mode is set to "degrees."
The Law of Sines can also be used to solve a triangle when two angles and one side are known.
Answer:
There were 84 students in 6th grade, 68 in 7th grade, and 90 in 8th grade.
Step-by-step explanation:
Given that Elk middle school has 264 students, and there are 84 students in the eighth grade, and there are 22 fewer seventh-grade students than sixth-grade students, to determine how many students there are in each grade, the following calculation must be performed:
(264 - 84) / 2) - 22 = X
(180/2) - 22 = X
90 - 22 = X
68 = X
6th grade = 84
7th grade = 68
8th grade = 90
Therefore, there were 84 students in 6th grade, 68 in 7th grade, and 90 in 8th grade.
Just divide the distance of each to point P by 2.
C would be 1 unit above and 2 units to the right of P.
D would be 1 unit below and 2 units to the right of P.
And so on...
Hope this helps