Ask question

Ask question

All categories

Natasha2012 [34]

3 years ago

11

Tacoma's population in 2000 was about 200 thousand, and has been growing by about 8% each year. If this continues, what will Tac

oma's population be in 2012?

1 answer:

Elena-2011 [213]3 years ago

5 0

Answer:

503634

Step-by-step explanation:

The formula for calculating future value:

FV = P (1 + r) n

FV = Future value

P = Present value

R = interest rate

N = number of years

200,000(1.08)^12

You might be interested in

Which of the following can be a Pythagorean triplets?:

PolarNik [594]

<h2>Answer :-</h2>

As we know that,

Pythagoras triplet

1) a² + b² = c²

Let

$\sf \: {2}^{2} + {2}^{2} = {4}^{2}$

$\sf \: 4 + 4 = 16$

8 ≠ 16

<h3>Hence, A can't be Pythagoras triplet</h3>

2) a² + b² = c²

$\sf \:5 {}^{2} + {12}^{2} = {13}^{2}$

$\sf \: 25 + 144 = 169$

169 = 169

<h3>Therefore, B can be Pythagoras triplet</h3>

3)a² + b² = c²

$\sf {3}^{2} + {5}^{2} = {6}^{2}$

$\sf 9 + 25 = 36$

34 ≠ 36

<h3>Hence, C can't be Pythagoras triplet</h3>

4) a² + b² = c²

$\sf {5}^{2} + {4}^{2} = {7}^{2}$

$\sf \: 25 + 16 = 49$

41 ≠ 49

<h3>Hence, D can't be Pythagoras triplet</h3>

<h2 /><h2>Therefore :-</h2>

Only B can be Pythagoras triplet.

3 0

3 years ago

Mia jogs 3 kilometers in 20 minutes. There are about 0.6 miles in a kilometer. What is Mia’s approximate speed in miles per minu

scoundrel [369]

Speed is the ditance traveled by a certain object given a certain time span. To solve this problem we need to divide the distance by the time given. Before that, the problem asked us to get the speed in terms of miles per minute and we are given a distance of 3 kilometer. We have to convert this to miles. 3km(0.6miles/km) = 1.8 miles. The speed is then 1.8/20 = 0.09mi/min.

3 0

3 years ago

Kim has finished eight of the ten math problems. phil has finished 2/5 of the math problems.How much more of the math has kim fi

MatroZZZ [7]

Kim has 4/5
phil has 2/5

kim has finsihed 2/5 more

4 0

3 years ago

Read 2 more answers

Suppose that X ∼ Geom(p) and Y ∼ Geom(r) are independent. Find the probability P (X < Y ).

Murrr4er [49]

$X,Y$ have joint density

$f_{X,Y}(x,y)=f_X(x)f_Y(y)=\begin{cases}pr(1-p)^x(1-r)^y&\text{for }x\ge0,y\ge0\\0&\text{otherwise}\end{cases}$

We can find $P(X$ by integrating the joint density over the region in $\Bbb R^2$ where $x$ in the first quadrant, i.e. above the line $y=x$ : $P(X$

using the fact that

$a^n=e^{n\ln a}\implies\displaystyle\int a^n\,\mathrm dn=\frac1{\ln a}e^{n\ln a}+C=\frac1{\ln a}a^n+C$

Then using the same property,

$P(X$

4 0

3 years ago

there are 24 students in mr. Simpsons math class 1/3 of the students received an a on a recent test how many students received a

Ivan

Answer:

8 students received an A.

Step-by-step explanation: 1/3*24=8

6 0

3 years ago