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Igoryamba
3 years ago
15

At $350 per person, an airline anticipates selling 200 tickets for a particular flight. At $450 per person the airline anticipat

es selling 100 tickets for the same flight .
Mathematics
1 answer:
DedPeter [7]3 years ago
5 0

Answer:

C =-x + 550

Step-by-step explanation:

Complete question

<em>At $350 per person, an airline anticipates selling 200 tickets for a particular flight. At $450 per person the airline anticipates selling 100 tickets for the same flight .Find the linear equation between the cost per ticket and the number of tickets.</em>

<em></em>

Find the complete question attached

Let x be the total number of tickets sold

C be the cost per ticket

If C = $350, x = 200

when C = $450, x = 100

Get the slope

m = C2-C1/x2-x1

m = 450-350/100-200

m = 100/-100

m = -1

Substituting into the point slope form of the equation;

C - C1 = m(x-x1)

Substituting m = -1, C1 = 350 and x1 = 200

C - 350 = -1(x-200)

C - 350 = -x + 200

C = -x + 200 + 350

C = -x + 550

Hence the required linear equation is C =-x + 550

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Sarah has 284 coins in a piggy bank with a total value of $22.78. Sarah has 173 pennies, 5 more dimes than nickels, the rest are
pickupchik [31]
Let P = number of coins of pennies (1 penny = 1 cent)
Let N = number of coins of nickels (1 nickel = 5 cents)
Let D = number of coins of dimes (1 dime = 10 cents)
Let Q = number of coins of quarters (1 quarter = 25 cents)

a) P + N + D + Q = 284 coins, but P = 173 coins, then:
173 + N + D + Q =284 coins
(1)  N + D + Q = 111 coins

b) D = N + 5 OR D - N =5 coins
(2) D - N = 5 coins

c) Let's find the VALUE in CENTS of (1) that is N + D + Q = 111 coins
5N + 10D + 25 Q = 2,278 - 173 (1 PENNY)
(3) 5N + 10D + 25Q = 2105 cents
Now we have 3 equation with 3 variables:

(1)  N + D + Q = 111 coins
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(3) 5N + 10D + 25Q = 2105 cents
Solving it gives:
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22 coins D ( x 10 = 220 cents)
72 coins D ( x 25 = 1,800 cents)
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proof:
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7 0
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