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Charra [1.4K]
3 years ago
11

Two solutions of differently concentrations of acid are mixed creating 40 mL of a soul union that is 32% acid one-quarter of the

soulutiob is made up of 20% acid soulution. The remaining three quarters is made up of a solution of unknown concentration c. Which equation can be used to determine c, the unknown.
Mathematics
1 answer:
AleksAgata [21]3 years ago
5 0

Answer: Three quarters (30 ml) is made up of a 36% acid solution.

Step-by-step explanation:

Since we have given that

Total amount of solution = 40 ml

One- quarter of the solution is given by

\frac{1}{4}\times 40\ ml\\\\=10\ ml

Three-quarter of the solution is given by

\frac{3}{4}\times 40\\\\=30\ ml

According to question, we have

10 ml of solution is made up of = 20% of acid solution

30 ml of solution is made up of = say<em> 'c </em>' of acid solution

40 ml of solution is made up of = 32 % of acid solution

So, our equation becomes,

10\times 0.2+30\times c=40\times 0.32\\\\2+30c=12.8\\\\30c=12.8-2\\\\30c=10.8\\\\c=\frac{10.8}{30}\\\\c=0.36\\\\c=36\%

Hence,  three quarters (30 ml) is made up of a 36% acid solution.

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