<span>a.
</span>The frequency of the dominant allele: ___0.4______
<span>b.
</span>The frequency of the recessive allele: ____0.6_____
<span>c.
</span>The percentage of mice that are homozygous
dominant: __16%_______
<span>d.
</span> The
percentage of mice that are heterozygous: _48%________
<span>e.
</span>The percentage of mice that are homozygous
recessive: __36%_______
Let us assign the dominant allele (that of brown hair) letter R
while
We assign the recessive
allele (that of white hair) letter r
We then note down the
Hardy-Weinburg equation p2 + 2pq + q2 = 1
Brown fur population (p2
+ 2pq) = 64% = 0.64
White fur population (q2) = 36% = 0.36
Then we also remember that the frequencies of both allele
add up to 1 (p + q = 1);
Therefore q = ü.36
= 0.6
P = 1 – q = 1 – 0.6 = 0.4
The heterozygous population will be 2*0.6*0.4 = 0.48 = 48%
Homozygous domain population will therefore be (64% - 48%) =
16%
This type of reactions are known as Neutralization<span> reactions!! HOPE THAT HELPED!</span>
Three characteristics that are used to classify prokaryotes is by their shape, how they move, and how they get energy. Prokaryotes are only found in plants and bacteria because they need a cell wall to keep their structures.
Your answer is: D) By shape, how they move, and how they get energy
Have an amazing day!
Living things have cells, can reproduce, maintain good metabolism, maintain homeostasis, react to their environment, and grow/develop
