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igomit [66]
4 years ago
11

Order the numbers from least to greatest: 17/7, 2.7, 2.15, 2.105

Mathematics
1 answer:
sattari [20]4 years ago
6 0
2.105,2.15,2.428 (17/7),2.7 is your answer
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16x²-81=0 solve the following quadratic equation
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16x^2-81=0\\\\(4x)^2-9^2=0\\\\(4x-9)(4x+9)=0\iff4x-9=0\ \vee\ 4x+9=0\\\\4x=9\ \vee\ 4x=-9\\\\x=\frac{9}{4}\ \vee\ x=-\frac{9}{4}


or\\\\16x^2-81=0\\\\16x^2=81\ \ \ \ /:16\\\\x^2=\frac{81}{16}\\\\x=\pm\sqrt\frac{81}{16}\\\\x=-\frac{\sqrt{81}}{\sqrt{16}}\ \vee\ x=\frac{\sqrt{81}}{\sqrt{16}}\\\\x=-\frac{9}{4}\ \vee\ x=\frac{9}{4}
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3 years ago
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Find 6 rational numbers between -2/3 and 1/2?
a_sh-v [17]

Answer:

-3/6 -2/6 -1/6 0/6 1/6 2/6

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3 years ago
Solve the system by elimination. State whether the system has one solution, infinite solutions, or no solution.
lukranit [14]
I'm not sure I'm right, I'm not all that good at elimination but I think the answer is y = 13. So I guess the answer would be A. one solution
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4 years ago
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NutritionCalc Plus uses the equations from the National Academy of Medicine to calculate the Estimated Energy Requirement (EER)
olga nikolaevna [1]

Answer:

The correct option is (A).

Step-by-step explanation:

The equation for the Estimated Energy Requirement (EER) of 19 or more years older men is:

EER = 662 - (9.53 \times AGE) + PA \times (15.91 \times WT + 539 \times HT)

Here,

AGE = age counted in years

PA = appropriate physical activity factor

WT = weight in kilograms

HT = height in meters

The physical activity factor for men and women is:

Activity Level       PA (men)      PA (Women)

Sedentary              1.00                1.00

    Low                    1.11                1.12

  Active                   1.25                1.27

Very Active              1.48                1.45

Given:

AGE = 22 year-old male college student

PA = low = 1.11

WT = 180 pounds = 81.6466 kg

HT = 5'10" = 1.778 m

Compute the value of EER as follows:

EER = 662 - (9.53 \times AGE) + PA \times (15.91 \times WT + 539 \times HT)

        = 662 - (9.53 \times 22) + 1.11 \times (15.91 \times 81.6466 + 539 \times 1.778)\\\\=662-209.66+1.11\times (1298.997406+958.342)\\\\=452.34+2505.64674066\\\\=2957.98674066\\\\\approx 2962

Thus, the EER for a 22-year-old male college student is approximately 2962 kcal.

The correct option is (A).

6 0
3 years ago
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gulaghasi [49]

Answer:4.64

Step-by-step explanation: I took the test on this and it was correct

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