First, some housekeeping:
cos = 12/13 is incomplete; "cos" must have an argument (input).
cos x = 12/13 is fine; here "cos" has the argument (input) x.
Given that cos x = 12/13, find sin x. To do this, we'll need to find the length of the opposite side, given that the hypo length is 13 and the adj. side length is 12.
12^2 + opp^2 = 13^2, or opp^2 = 169-144 = 25.
Then the opp side could be either 5 or -5. Let's assume that it's +5, and that angle x is in the first quadrant.
Then sin x = opp / hyp = 5/13 (answer)
cos 2 is an entirely different kind of problem. Here you are told what the argument (input) to the cosine function is (it is 2, which here means 2 radians).
Using a calculator: cos 2 = -0.416. Note that the angle 2 rad is in QII, which is why the "adjacent side" is negative and also why the cos of 2 is negative.
Answer: each triangle drawing is 180 degrees total, 2 triangles is 360 etc.
Step-by-step explanation:
By first principles, the derivative is
Use the binomial theorem to expand the numerator:
where
The first term is eliminated, and the limit is
A power of 
in every term of the numerator cancels with in the denominator:
Finally, each term containing approaches 0 as 
, and the derivative is
Answer:
All real numbers
Step-by-step explanation:
The domain represents the x-coordinates, so you can see on the graph that it goes all the way out to both the left and right directions, meaning it covers all the negative numbers, and all the positive numbers. The question is trying to trick you into thinking about the range, but forget about the y-axis for this one.
Answer:
4,a
5.d
6.c
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Step-by-step explanation:
