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marissa [1.9K]
3 years ago
8

Please help this pea sized brain 8 x (-2) : 4 x 0 =

Mathematics
1 answer:
OlgaM077 [116]3 years ago
8 0

Answer:

undefined

Step-by-step explanation:

8 x (-2) : 4 x 0

undefined because denominator is zero

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Ming earns $35 washing 7 windows. At this rate, how much does Ming earn washing 8 windows?​
damaskus [11]

Answer:

$70

Step-by-step explanation:

$35 = 7 windows

$35 + $35 = $70

3 0
3 years ago
Read 2 more answers
Point B has coordinates ​(1​,2​). The​ x-coordinate of point A is negative 8. The distance between point A and point B is 15 uni
olchik [2.2K]

Answer:

The point A will be  (-8,14) or (-8,-10).

Step-by-step explanation:

Point B has coordinates (1,2) and the x-coordinate of point A is - 8.

Let us assume that the coordinates of point A are (-8,k).

Now, given that the point A is 15 units apart from point B.

Therefore, from the distance formula, we can write that  

\sqrt{(1 - ( -8))^{2} + (2 - k)^{2}} = 15

Now,squaring both sides, we get  

(1 - ( -8))^{2} + (2 - k)^{2} = 225

⇒ (2 - k)^{2} = 225 - 9^{2} = 144

⇒ 2 - k = ± 12

⇒ k = 14 or -10.

Therefore, the point A will be  (-8,14) or (-8,-10). (Answer)

We know that the distance between two points on the coordinate plane (x_{1}, y_{1}) and (x_{2}, y_{2}) is given by  

\sqrt{(x_{1} - x_{2})^{2} + (y_{1} - y_{2})^{2}}.

7 0
3 years ago
Which statement describes the inverse of m(x) = x2 – 17x?
stealth61 [152]

Answer:

The correct option is;

The \ domain \ restriction \ x \geq \dfrac{17}{2} \ results \ in \ m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }}

Step-by-step explanation:

The given information is that m(x) = x² - 17·x

The above equation can be written in the form;

y = x² - 17·x

Therefore;

0 = x² - 17·x - y

From the general solution of a quadratic equation, 0 = a·x² + b·x + c we have;

x = \dfrac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a}

By comparison to the equation,0 = x² - 17·x - y, we have;

a = 1, b = -17, and c = -y

Substituting the values of a, b and c into the formula for the general solution of a quadratic equation, we have;

x = \dfrac{-(-17)\pm \sqrt{(-17)^{2}-4\times (1) \times (-y)}}{2\times (1)} = \dfrac{17\pm \sqrt{289+4\cdot y}}{2}

Which can be simplified as follows;

x =  \dfrac{17\pm \sqrt{289+4\cdot y}}{2}= \dfrac{17}{2} \pm \dfrac{1}{2}  \times \sqrt{289+4\cdot y}} = \dfrac{17}{2} \pm \sqrt{\dfrac{289}{4} +\dfrac{4\cdot y}{4} }}

And further simplified as follows;

x = \dfrac{17}{2} \pm \sqrt{\dfrac{289}{4} +y }} = \dfrac{17}{2} \pm \sqrt{y + \dfrac{289}{4} }}

Interchanging x and y in the function of the inverse, m⁻¹(x), we have;

m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }}

We note that the maximum or minimum point of the function, m(x) = x² - 17·x found by differentiating the function and equating the result to zero, gives;

m'(x) = 2·x - 17 = 0

x = 17/2

Similarly, the second derivative is taken to determine if the given point is a maximum or minimum point as follows;

m''(x) = 2 > 0, therefore, the point is a minimum point on the graph

Therefore, as x increases past the minimum point of 17/2, m⁻¹(x) increases to give;

The \ domain \ restriction \ x \geq \dfrac{17}{2} \ results \ in \ m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }} to increase m⁻¹(x) above the minimum.

8 0
3 years ago
Find the area and the perimeter of the shaded region
lyudmila [28]

Answer:

area: 41.04 cm² ; perimeter 35.8 cm

Step-by-step explanation:

Perimeter of shaded area = 1/4 perimeter of circle + line AC = ¼ * 3.14 * 2 * 12 + √(12² + 12²) = 18.84 + 12√2 cm = 35.8 cm

Area of Shaded Region = 1/4 area of circle - area of triangle = ¼ * 3.14 * 12² - ½ . 12 * 12

= (¼ * 3.14 - ½) * 12² = 41.04 cm²

8 0
3 years ago
Brainliest!!
AlladinOne [14]

Answer:

d

Step-by-step explanation:

BC supplementary means they add up to 180 and answer d adds up to 180

6 0
3 years ago
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