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Alenkinab [10]
3 years ago
14

Which expression can be used to find 80% of 120?

Mathematics
1 answer:
Leya [2.2K]3 years ago
5 0
Answer
(0.8) (120)
80/100 is 80%
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Using the list below, what is the ratio of goats to the total number of animals at the zoo? Animals at a Petting Zoo Chickens 2
NemiM [27]

Answer:

Ratio of goat to total number of animals at the zoo = 2 : 5

Step-by-step explanation:

Chickens = 2

Deer = 4

Donkeys = 3

Goats = 6

Total animals at the zoo = 15

what is the ratio of goats to the total number of animals at the zoo?

Ratio of goat to total number of animals at the zoo = 6 : 15

= 6/15

= 2/5

Ratio of goat to total number of animals at the zoo = 2 : 5

3 0
2 years ago
Write two equivalent fractions for 5/10
shtirl [24]
1/2 and 10/20

to get 1/2 you have to divide 5/10 by 5:

  5   /   5          1     
-----          =   ----- 
 10  /   5          2

to get 10/20 you have to multiply 5/10 by 2:

  5   *   2          10
-----           =    ----
 10  *   2          20

Hope it helps! =)
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3 years ago
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lana66690 [7]

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The answer would be 7-x.
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Find the minimum sample size needed to estimate the percentage of Democrats who have a sibling. Use a 0.1 margin of error, use a
Brums [2.3K]

Answer:

The minimum sample size is  n  =135

Step-by-step explanation:

From the question we are told that

   The confidence interval is ( lower \ limit  = \  0.44,\ \ \   upper \ limit  = \ 0.51)

    The margin of error is  E =  0.1

   

Generally the sample  proportion can be mathematically evaluated as

     \r p = \frac{ upper \ limit  + lower \ limit }{2}

    \r p = \frac{ 0.51 + 0.44}{2}

    \r p = 0.475

Given that the confidence level is  98% then the level of significance can be mathematically evaluated as

         \alpha = 100 -  98

        \alpha = 2\%

        \alpha =0.02

Next we obtain the critical value of  \frac{\alpha }{2} from the normal distribution table  

   The value is

        Z_{\frac{\alpha }{2} } =  2.33

Generally the minimum sample size is evaluated as

      n  =[ \frac { Z_{\frac{\alpha }{2} }}{E} ]^2 *  \r p (1- \r p )

     n  =[ \frac { 2.33}{0.1} ]^2 *  0.475(1- 0.475 )

     n  =135

6 0
3 years ago
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