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Alenkinab [10]
3 years ago
14

Which expression can be used to find 80% of 120?

Mathematics
1 answer:
Leya [2.2K]3 years ago
5 0
Answer
(0.8) (120)
80/100 is 80%
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Boris pushes a 5 lb. box 6 feet in 2 seconds. He has _____.
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Answer:

B.

Step-by-step explanation:

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MUST BE CORRECT ANSWER HELP ASAP
Nina [5.8K]

Answer:

40287600 = B. 4 x 10^{7}

Step-by-step explanation:

<u>We first have to do the multiplication of the numbers given:</u>

19 * 2,120,400

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<u>Now we have to figure out how many digits are after the number 4:</u>

4, 0 2 8 7 6 0 0

7 digits

Meaning that we need an exponent of 7 for it to be in scientific notation, giving us with the answer B. 4  x 10^{7}

6 0
3 years ago
If f(x) = 2x2 - x, find f(-3).
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f(x)=2x^2-x


Substitute the value of x = -3 to the equation:


f(-3)=2(-3)^2-(-3)=2(9)+3=18+3=21

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3 years ago
(4,2);slope=3<br><br>help me out
ivolga24 [154]
We have a point and a slope, so let's use the point slope formula!

(y - y1) = m(x - x1)
where
x1=4
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3 years ago
the first group of students consists of 10 and their average age was 13 years old the next group consisted of 30 students and th
Kazeer [188]

Answer: The average was 9 years old find the average age of both groups is 10 years old.

Step-by-step explanation:

Formula foe average : \text{Average} =\dfrac{\text{Sum of all observations}}{\text{Number of observations}}

Given : The first group of students consists of 10 and their average age was 13 years old.

i.e. 13=\dfrac{\text{Sum of ages of students of first group}}{10}\\\\\Rightarrow\ \text{Sum of ages of students of first group}=13\times10=130      (1)

The next group consisted of 30 students and their average was 9 years old.

i.e. 9=\dfrac{\text{Sum of ages of students of next group}}{30}\\\\\Rightarrow\ \text{Sum of ages of students of nextgroup}=9\times30=270      (2)

Then from (1) and (2) , the sum of both groups (first group and next group )students = 130+270 =400

Combined students of both groups (first and next group )= 10+30=40

Now , the average of both groups =\dfrac{\text{Sum of combined students}}{\text{combined students}}

=\dfrac{400}{40}=10

Hence, the average was 9 years old find the average age of both groups is 10 years old.

4 0
3 years ago
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